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Daniel [21]
2 years ago
12

If a football team has a 90% chance of making a field goal for 3 points and a 35% chance of making a touchdown for 7 points, fin

d the expected value of a touchdown.
PLEASE HELP!!!

Mathematics
2 answers:
Svetlanka [38]2 years ago
4 0

2.7 points (my guess)

Svetllana [295]2 years ago
3 0

Answer: The expected value of touchdown is 2.45.

Step-by-step explanation:

Since we have given that

Probability of making a field goal for 3 points = 90%

Probability of making a touchdown for 7 points = 35%

So, Expected value of a touchdown would be

\sum xp(x)=7\times \dfrac{35}{100}=\dfrac{245}{100}=2.45

Hence, the expected value of touchdown is 2.45.

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Explanation: The zeroes of f(x) are the value/s of x such that f(x) = 0. So, we need to find the values of x in the equation f(x) = 0.

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