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ddd [48]
3 years ago
12

A certain city has one chance in two of receiving rain on June 1, one chance in five of receiving rain on July 1, and two chance

s in three of receiving rain on August 1. What is the probability that the city will receive rain on none of these days?
2/15
2/5
14/15
Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0
2/5 and it makes me right more stuff so there
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I need help please and thank you
d1i1m1o1n [39]

Answer:

8.08

Step-by-step explanation:

8 0
3 years ago
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The edge of each cube used to build this rectangular prism is 1/3 inch long. Which equation shows the volume of the prism, in cu
KiRa [710]
(1/3) cubed, since the equation for the volume of a cube is an edge, cubed
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3 years ago
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Pedro is saving part of his allowance to buy a gift for his teacher. At the end of 10 weeks he has saved $95.50 . Pedro saved th
aev [14]

Answer:

Pedro saves $9.55 each week.

4 0
3 years ago
Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y
DiKsa [7]

The area of the surface is given exactly by the integral,

\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx

We have

y(x)=\dfrac15x^5\implies y'(x)=x^4

so the area is

\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the i-th subinterval are, respectively,

\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2

r_i=\dfrac{5-0}{10}i=\dfrac i2

with midpoint

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4

with 1\le i\le10.

Over each subinterval, we interpolate f(x)=\sqrt{1+x^8} with the quadratic polynomial,

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

Then

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It turns out that the latter integral reduces significantly to

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)

which is about 651.918, so that the area is approximately 651.918\pi\approx\boxed{2048}.

Compare this to actual value of the integral, which is closer to 1967.

4 0
3 years ago
What’s 1500 times 150000
kotykmax [81]

Use long multiplication to evaluate.

225000000


4 0
3 years ago
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