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timurjin [86]
3 years ago
13

Find the zeros of f(x) = (x -3)^2 - 49

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0
We have the function f(x)=(x-3)^2-49.
This equals...
0 = (x-3)^2 - 49
Add 49.
49 = (x-3)^2
Square both sides.
<span>±7 = x-3
</span><span>± 10 = x</span>
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