Find the zeros of f(x) = (x -3)^2 - 49

1 answer:

soldier1979 [14.2K]2 years ago

5 0

We have the function f(x)=(x-3)^2-49.
This equals...
0 = (x-3)^2 - 49
Add 49.
49 = (x-3)^2
Square both sides.
<span>±7 = x-3
</span><span>± 10 = x</span>

You might be interested in

The next weekend after the camping trip, Lin and Diego each decide to cook a large batch of oatmeal to have breakfasts ready for

dlinn [17]

He should boil 12.5 gallons of water for 5 cups of oats.

4 0

2 years ago

1/7^3 in simplest form

Blababa [14]

Answer:

1/343

Step-by-step explanation:

If you multiply 1/7*1/7*1/7 (1/7^3) then you would get 1/343.

5 0

3 years ago

What is the perimeter and area of a 5 x 5 square?

JulsSmile [24]

Perimeter is 20 and the area is 25

5 0

2 years ago

Solve for c. -3b+ac=c-4. Please show all work.

Luden [163]

-3b+ac=4
Move c to the left and - 3b to the right
ac-c=-4+3b
Now factor by c at the left
c(a-1)=-4+3b
Divide the right by a-1
C=(-4+3b)/(a-1)

6 0

2 years ago

Read 2 more answers

Please help this is the only question im stuck on

Lemur [1.5K]

I think a, bc for the x it’s 2x and the y is +5

8 0

2 years ago