Find the zeros of f(x) = (x -3)^2 - 49

1 answer:

soldier1979 [14.2K]2 years ago

5 0

We have the function f(x)=(x-3)^2-49.
This equals...
0 = (x-3)^2 - 49
Add 49.
49 = (x-3)^2
Square both sides.
±7 = x-3
± 10 = x

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4) To find the value of b, substitute the point into the equation.

5) Convert the equation to slope y-int. form to find the slope.

6) When a line has an undefined slope, the slope y-int. will look either like
y = __ (forms horizontal line) or x = __ (forms vertical line).
To find the perpendicular of these lines, turn y to x / x to y.
To find the value of __, look at the point located in the line, so if x = ___
passes through (5,3), then x = 5 because x = 5 in the point. So the
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Use online practice tests and other sources if you don't understand.

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