Please explain to me how to solve for x. Picture attached

Mathematics

1 answer:

nexus9112 [7]3 years ago

5 0

Answer:

35) x = 3 1/3

Step-by-step explanation:

for each of these parallelograms, the diagonals are congruent

in #35, DT = RT so you can set their expressions equal to each other

22 = 6x + 2

20 = 6x

20/6 = x

10/3 = x (simplified)

You might be interested in

Solve the equation 2 (x - 1/2)<br> = 3(5 - 2x) . Show the steps in your solution.

Andreyy89

(2x-2/2) = (15-6x)
2x-1 = 15 -6x
2x+6x = 15 +1
8x = 16
8x/8 = 16 /8
x = 2

7 0

3 years ago

Z varies directly with x and inversely with y. When x=6 and y=2, .z=15. Write function that models variation. Then, find z when

tester [92]

$\bf \begin{array}{cccccclllll}
\textit{direct proportional variation}\\\\\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&& y={{ k }}x
\end{array}\\ \quad \\$

$\bf \textit{inverse proportional variation}\\\\
\begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{ k}}}{x}
\end{array}$

$\bf \\\\
-------------------------------\\\\
\textit{z varies directly with x}\implies z=kx
\\\\
\textit{and inversely with y}\implies z=\cfrac{kx}{y}
\\\\\\
\textit{we also know that}\quad 
\begin{cases}
x=6\\
y=2\\
z=15
\end{cases}\implies 15=\cfrac{k\cdot 6}{2}\implies 30=6k$

$\bf \cfrac{30}{6}=k\implies \boxed{5=k}\impliedby \textit{constant of variation}
\\\\\\
thus\implies z=\cfrac{5x}{y}\\\\
-------------------------------\\\\
\textit{what's "z" when }
\begin{cases}
x=4\\
y=9
\end{cases}\implies z=\cfrac{5\cdot 4}{9}$

4 0

4 years ago

I need to know number one

vlada-n [284]

I hope this helps you