Find the first term of the following geometric sequence ----,42,126,378,1,134

1 answer:

8 0

Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...

126/42=378/126=1134/378=3

The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:

42=a(3)^(2-1)

42=3a

a=14

So the first term is 14.

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Heights for women are bell-shaped with a mean of 65 inches and standard deviation of 2.5 inches. If a random sample of 16 women

loris [4]

Answer:

μ= 65 inches; σ= 0.625 inch

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed(bell-shaped) random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 65, \sigma = 2.5$

By the central limit theorem, the sample of 16 will have:

$\mu = 65, \sigma = \frac{2.5}{\sqrt{16}} = 0.625$

So the correct answer is:

μ= 65 inches; σ= 0.625 inch

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slega [8]

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, $c^2=a^2+b^2-2abcos\theta$

We the plug in values: $(CB)^2+6^2+5^2-2*6*5*cos74$

and solve that CB is around 6.7

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3 years ago

How do you solve this? Matt had some candy to give to his four children. He first took two pieces for himself and then evenly di

Rasek [7]

You work it backwards.

-- If there were 4 children and each child got 4 pieces,
then the children got (4 x 4) = 16 pieces altogether.

-- That's what was left after he took 2 pieces for himself.
So he started with (16 + 2) = <em>18 pieces</em>.

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3 years ago

Read 2 more answers

Which expression is equivalent to 9q2-(3q - 7) +5q??<br> ) ?<br> 3

lesantik [10]

$9q^2-(3q - 7) +5q= \\\\=9q^2-3q + 7 +5q= \\\\=9q^2+2q + 7$