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Dovator [93]
4 years ago
9

Why can protons not be rubbed off one material and transferred to the other?

Physics
1 answer:
Pani-rosa [81]4 years ago
7 0
I think it is that protons are stuck with the neutrons in a strong force that is in the nucleus
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An object that is moving in a linear path with an acceleration in the direction of motion has a(n) ______________ velocity. cons
Kamila [148]
The correct answer is increasing velocity.

In fact, the fact that the object has an acceleration different from zero means that the velocity of the object is changing. If the acceleration is in the direction of the motion, then it is a positive acceleration, therefore the velocity is increasing. The law of velocity for an object in accelerated motion is in fact
v(t)=v_0 + at
where v_0 is the initial velocity, a the acceleration and t the time. When a is positive (same direction of the motion), then the term (at) is increasing as t becomes larger, therefore the velocity v(t) is increasing as well.
8 0
4 years ago
A microscope has an eyepiece with a 1.8 cm focal length and a 0.8 cm focal length objective lens. Assuming a relaxed eye, calcul
igomit [66]

Answer:

0.848\ \text{cm}

232.66

Explanation:

N = Near point of eye = 25 cm

f_o = Focal length of objective = 0.8 cm

f_e = Focal length of eyepiece = 1.8 cm

l = Distance between the lenses = 16 cm

Object distance is given by

v_o=l-f_e\\\Rightarrow v_o=16-1.8\\\Rightarrow v_o=14.2\ \text{cm}

u_o = Object distance for objective

From lens equation we have

\dfrac{1}{f_o}=\dfrac{1}{u_o}+\dfrac{1}{v_o}\\\Rightarrow u_o=\dfrac{f_ov_o}{v_o-f_o}\\\Rightarrow u_o=\dfrac{0.8\times 14.2}{14.2-0.8}\\\Rightarrow u_o=0.848\ \text{cm}

The position of the object is 0.848\ \text{cm}.

Magnification of eyepiece is

M_e=\dfrac{N}{f_e}\\\Rightarrow M_e=\dfrac{25}{1.8}\\\Rightarrow M_e=13.89

Magnification of objective is

M_o=\dfrac{v_o}{u_o}\\\Rightarrow M_o=\dfrac{14.2}{0.848}\\\Rightarrow M_o=16.75

Total magnification is given by

m=M_eM_o\\\Rightarrow m=13.89\times 16.75\\\Rightarrow m=232.66

The total magnification is 232.66.

3 0
3 years ago
What's the formation and motion of galaxies
Natalka [10]

Answer:

is this have picture with it so I can solve

8 0
3 years ago
Justin drives his unicycle 7.0 m/s northward. How long will it take him (in seconds) to travel 12 km?
Aleksandr-060686 [28]

Answer:

The time required is 28.5 [min]

Explanation:

We can find the time using the kinematic equation, but first, we must convert the distance to travel in meters.

x = distance = 12 [km] = 12000 [m]

velocity = 7 [m/s]

Tt = \frac{x}{v} \\t=\frac{12000}{7} \\t=1714 [s] = 28.5 [min]

7 0
3 years ago
The speed of light in air is 3 x 108 m/s. The speed of light in ice is 2.29 x 108 m/s. What is the refractive index from air to
Studentka2010 [4]

Answer:

η = 1.31

Explanation:

The formula for the refractive index of from air to some other medium is given by the following formula:

\eta = \frac{c}{v}\\

where,

η = refractive index = ?

c = speed of light in air = 3 x 10⁸ m/s

v = speed of light in ice = 2.29 x 10⁸ m/s

Therefore, using these values in the equation we get:

\eta = \frac{3\ x\ 10^8\ m/s}{2.29\ x\ 10^8\ m/s} \\

<u>η = 1.31</u>

4 0
3 years ago
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