<u>Answer:</u> The energy released in the decay process is
<u>Explanation:</u>
The equation for the alpha decay of Ra-226 follows:
To calculate the mass defect, we use the equation:
Mass defect = Sum of mass of product - Sum of mass of reactant
We know that:
Putting values in above equation, we get:
(Conversion factor: 1 kg = 1000 g )
To calculate the energy released, we use Einstein equation, which is:
Hence, the energy released in the decay process is
Answer:
d. the same within the uncertainty of each measurement method
Explanation:
The density of an object and in general any physical property, has the same value regardless of the method used to measure it, either directly or indirectly. Since two completely different valid methods are used, the results must be the same, taking into account the level of precision of each of the methods.
Answer:
a)
b)
c) ΔK=
d)ΔK=
Explanation:
From the exercise we know that there is a collision of a sports car and a truck.
So, the sport car is going to be our object number 1 and the truck object number 2.
Since the two vehicles remain locked together after the collision the final mass is:
a) To find the velocity of the two vehicles just after the collision we must use linear's momentum principle
b) To find the speed the truck should have had so both vehicles stopped in the collision we need to use the same principle used before
c) To find the change in kinetic energy we need to do the following steps:
ΔK=
ΔK=
d) The change in kinetic energy where the two vehicles stopped in the collision is:
ΔK=
ΔK=
Answer:
See the answers below
Explanation:
This problem can be solved by means of the law of conservation of energy, which tells us that the energy between two points is conserved, that is, remains the same.
That is to say, we have two points, the point A where it starts to move and reaches the point B that is 1.5 [m] high, where it stops.
The key to solving this problem is to identify the types of energies at each point. At point A we have kinetic energy and potential energy where the block moves at speed 3 [m/s] at a height of 4 [m]. Whereas at Point B we only have potential energy, since the body is at a height of 1.5 [m], relative to the ground.
a)
Since between the displacement between points A and B there is a friction force, this friction force decreases the final energy in B, in this way the energy or work of the friction will have a negative sign.
Now replacing in the above equation.
b)
We must use the same equation, but this time eliminating the Working term due to friction.
As we can see without friction the block can reach a higher height
Answer:
Explanation:
The problem is based on Doppler's effect , for which expression is as follows
n is apparent frequency , n₀ is original frequency , V is velocity of light , v₀ is velocity of observer and v_s is velocity of source , both coming towards each other.
Putting the values
n = 302 .