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3 years ago

7

A school has a new flag that must be flown at last 52 feet high The current flagpole is 14 m tall How many meters taller does th

e new flagpole need to be? Round to the nearest tenth (One meter is about 3 28 feet)

1 answer:

ohaa [14]3 years ago

6 0

To start with, convert 52 feet into metres
1 Feet= 0.3048
52 feet= ?
The number of meters= 52*0.3048
The number of meters= 15.8496 metres

The school need to add a further 1.8496 metres

You might be interested in

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0

3 years ago

A long distance runner does a first lap around a track in exactly 50 seconds.As she tires.Each subsequent lap takes 20% longer t

madreJ [45]

Answer:

182 seconds

Step-by-step explanation:

Given:

Time taken for first lap is 50 seconds and each subsequent lap takes 20% longer than previous

Solution:

Time taken for first lap = 50 sec

For second lap

Each subsequent lap takes 20% longer than previous

Previous lap time = 50 sec

second lap = 50 + 20% of 50

second lap $=50+(\frac{20}{100}\times 50)$

second lap $= 50 + 10$

second lap $= 60\ sec$

For third lap

Each subsequent lap takes 20% longer than previous

Previous lap time = 60 sec

Third lap = 60 + 20% of 60

$Third\ lap = 60 + (\frac{20}{100}\times 60)$

$Third\ lap = 60+2\times 6$

$Third\ lap = 60+12$

$Third\ lap = 72\ sec$

Time taken for 3 laps is equal to sum of all three laps time.

$Tiem\ taken\ for\ 3\ lap = 50+60+72$

$Tiem\ taken\ for\ 3\ lap = 182\ sec$

Therefore, it takes 182 seconds (3 min, 2 seconds) to run three laps

6 0

3 years ago

at Mountain Park Middle School there are 250 7th grade students currently 32% of those students are in advanced math

makkiz [27]

Answer:

95

students in the seventh grade have taken swimming lessons.

Explanation:

We calculate

38

%

of

250

using the following formula:

x

=

250

×

38

100

x

=

25

0

×

38

10

0

(cancel by 10)

x

=

5

25

×

38

2

10

(cancel by 5)

x

=

5

×

19

38

1

2

(cancel by 2)

x

=

5

×

19

x

=

95

Step-by-step explanation:

7 0

3 years ago

In a triangle the sides has 82 degrees ,2x+10 degrees and x degrees what is x

yaroslaw [1]

Answer:

x = 29 1/3 degrees

Step-by-step explanation:

A triangle has 3 angle that total 180 degrees.

The three angles given are 82 degrees ,2x+10 degrees and x degrees.

So,

82+ (2x+10) + x = 180

Combine like terms.

92 + 3x = 180

Subtract 92 from each side

3x = 180 -92

3x = 88

divide each side by 3

3x/3 = 88/3

Change 88/ 3 to a mixed number

3 goes in to 88 29 times with 1 left over.

x = 29 1/3 degrees

4 0

2 years ago

Question 7 of 18

Delicious77 [7]

The more appropriate measures of center and spread are:

A. Better measure of spread: the interquartile range (IQR)
B. Better measure of center: the median

<h3>Which measures are best for the given data?</h3>

The better measure of the middle would be the median because mean is affected by low and high values which are present in the given data set.

As mean is not being used, standard deviation should not be used for the same reason. This leaves us with the interquartile range which is best because it does not take outliers into account.

Find out more on the Interquartile Range at brainly.com/question/12568713.

#SPJ1

3 0

2 years ago