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3 years ago

Find the angle represented by x. (rounded to the nearest tenth of a degree)

Mathematics

1 answer:

saw5 [17]3 years ago

3 0

X=.5 digressed bsquare +.2= 11.23987

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Parabola with vertex at (4, -2) and passes through<br> the point (2, 10)

amid [387]

Answer:

x2-x1/y2-y1=2-4/10--2=2-4/10+2=-2/12

=-6

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3 years ago

158.297 rounded each number to the nearest while number

Katarina [22]

Answer: 158

Step-by-step explanation:

158.297

It rounds to 158

since 0.297 < 0.5

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3 years ago

In a class of 32 students the mean height of the boys is 1.56 metres

mart [117]

Answer: JW.org is where you can find your answers.

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4 years ago

Jose bought a pair of sneakers, a gaming headset and a T-shirt for $77. The headset cost two times

Margarita [4]

Answer:

The cheapest item is T shirt costing $13.

Step-by-step explanation:

Let the cost of T shirt = $ m

So, the cost of the headset = $ (2m)

and, The cost of Sneakers = $ ( m + 25)

Total amount spent by Jose = $77

Now, According to the question:

$ m + $ (2m) + $ ( m + 25) = $77

or, 4m + 25 = 77 ⇒ 4m = 77 - 25 = 52

or, m = 52/4 = 13

⇒ The cost of one T- Shirt = m = $ 13

The cost of the headset = (2m) = 13 x 2 = $ 26

The cost of Sneakers = $ ( m + 25) = 13+ 25 = $ 38

As, out of all costs, $13 is the lowest cost

Hence, the cheapest item is T shirt costing $13.

3 0

3 years ago

What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.

Ahat [919]

The value of x in the equation $(x-5)^{2} +3(x-5)+9=0$ is x=(7+3 $\sqrt{3}i$ )/2,

(7-3 $\sqrt{3}i$ )/2.

Given equation $(x-5)^{2} +3(x-5)+9=0$ .

We have to find the solution of the equation.

Equation is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes $u^{2} +3u+9=0$

solution of a quadratic formula

x=-b± $\sqrt{b^{2} -4ac}$ /2a

on comparing with general form a=1,b=3, c=9

u=-3± $\sqrt{3^{2} -4*1*9} /2$

=-3± $\sqrt{9-36}/2$

=-3± $3\sqrt{-27}/2$

=-3± $3\sqrt{3} i/2$

$u_{1} =-3$ +3 $\sqrt{3}/2$ , $u_{2}$ =-3-3 $\sqrt{3}/2$

put the values of $u_{1}$ in equation 1

x-5= $u_{1}$

x-5=-3+ $3\sqrt{3} /2$

x=-3+3 $\sqrt{3}i/2+5$

x=7+3 $\sqrt{3} i/2$

put the values of $u_{2}$ in equation2

x-5= $u_{2}$

x-5=-3-3 $\sqrt{3} /2$

x=7-3 $\sqrt{3}/2$

Hence the values of x are 7+3 $\sqrt{3}i/2$ , 7-3 $\sqrt{3}i/2$ .

Learn more about equation at brainly.com/question/2972832

#SPJ4

5 0

2 years ago