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3 years ago

Express 3^2 = x as a logarithmic equation.

1 answer:

azamat3 years ago

6 0

Log shows exponent in wich you need to put base to get x,
so you have the only choice here it is A,
 3^2 = x , here is the base 3, exponent 2,
A. Log base of (3) x = 2

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Which function is equivalent to F(x)=-4(x+7)^2-6?

Gemiola [76]

$\huge\mathfrak\orange{answer}$

Simplify this quadratic function given in vertex form into standard form by simplifying the exponents and adding like terms.

$f(x) = \red{-4(x+7)^2 - 6}$

$f(x) = -4(x^2 + 14x + 49) - 6$

$f(x) = -4x² - 64x - 196 - 6$

$\underline{f(x) = -4x² - 64x - 202}$

(good luck :) and mark me brainliest if you're satisfied with my answer)

7 0

3 years ago

Find the value of the expression if x=-7

LUCKY_DIMON [66]

Answer: -16

Step-by-step explanation:

49 would be the result of -7 squared. Due to the fact it is negative, it would cancel out to be positive.

For the numerator, 49-1 is equivalent to 48.

48/x+4

-7+4 = -3

48/-3

= -16

5 0

2 years ago

Can one of you lovely people help me please ?

saveliy_v [14]

Answer:

the answer is

C. = x=22.82

4 0

2 years ago

Read 2 more answers

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

Find the value of y

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

Find the values of x

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Please Help Me With Functions!!!!!!

denpristay [2]

Answer:

I don't know how to do it the question

3 0

3 years ago