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dolphi86 [110]
3 years ago
15

Can you help me with this?

Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

<h2>88 units squared</h2>

Step-by-step explanation:

I'll solve both of the triangles separately and then add it all together.

Triangle 1;

5*4*0.5 =

10

Triangle 2;

5 * 4 * 0.5 =

10

Rectangle;

17 * 4 =

68

(10 + 10 + 68) =

88

Thus, the area of the trapezoid is 88un.^2

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Oduvanchick [21]
Let’s convert 3 kilograms to 3000 grams just to make things easier.

650 * 4 = 2600 grams. This is the total weight of the 4 blocks.

To find the weight of the final block, 3000 - 2600 = 400 grams

4 0
3 years ago
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Drag the correct graph to the box under the equation it corresponds to.<br><br> HELP YOU GUYS
ra1l [238]

Answer:

<h2>See below</h2>

Step-by-step explanation:

I can't drag and drop the graphs, but I can graph the equations shown. Then, all you will have to do is match the graphs shown the the graph that I will provide.

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I'm always happy to help :)

5 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
4 years ago
The range of the secant function is?
Brrunno [24]
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Answer:

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