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Darya [45]
3 years ago
15

Write as a monomial in standard form (−4x^2ya^3)^2

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0

Answer:

16x⁴y²a⁶

Step-by-step explanation:

(−4x²ya³)^2

(-4)² × (x²)² + (y)² × (a³)²

16 × x⁴ × y² × a⁶

16x⁴y²a⁶

svetoff [14.1K]3 years ago
7 0

The given monomial in standard form is 16a^6x^4y^2

<em><u>Solution:</u></em>

A Monomial in standard form is the product of one or more factors: a constant coefficient and one factor for each variable in the expression.

<em><u>Given monomial is:</u></em>

(-4x^2ya^3)^2

We use the following law of exponents to solve the above monomial:

(ab)^n = a^nb^n\\\\(a^n)^m = a^{mn}

Using these in given monomial, we get

(-4x^2ya^3)^2 = (-4)^2(x^2)^2(y)^2(a^3)^2

Now applying the law of exponent (a^n)^m = a^{mn} we get,

(-4)^2(x^2)^2(y)^2(a^3)^2 = 16x^{2 \times 2}y^2a^{3 \times 2} = 16x^4y^2a^6

A monomial is in standard form when its term of highest degree is first, its term of 2nd highest is 2nd etc

Writing in standard form we get,

\rightarrow 16a^6x^4y^2

Thus the given monomial is written in standard form

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