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amid [387]
2 years ago
15

What is (9x^4-x^2y^2-5y^4)-(3x^4+2x^2y^2-7y^4)

Mathematics
1 answer:
g100num [7]2 years ago
8 0
(9x⁴ - x²y² - 5y⁴<span>) - (3x</span>⁴ + 2x²y² - 7y⁴<span>)
</span>9x⁴ - x²y² - 5y⁴ - 3x⁴ - 2x²y² + 7y⁴
6x⁴ - 3x²y² + 2y⁴
You might be interested in
How do you find an average?
wlad13 [49]

Answer:

Finding the average is a very straightforward concept. If you have a set of numbers, the average is found by adding all numbers in the set and dividing their sum by the total number of numbers added in the set.

example;

16, 17, 5, 27, 30, 20, 4, 1, 19, 9

add all 10 of these numbers together

16 + 17+ 5+27+30+4+1+19+9 = 148

divide 128 by 10

148 / 10 = 14.8

14.8 is the average

4 0
2 years ago
The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the fun
Svetllana [295]
H(x)=-16t^2+300

The average rate is the change in h divided by the change in t, mathematically:

r=(h(3)-h(0))/(t2-t1), in this case:

r=(-16*9+300-0-300)/(3-0)

r=-144/3

r= -48 ft/s
5 0
3 years ago
Read 2 more answers
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
How can data or a graph be misleading?
Shtirlitz [24]
The correct answer should be
B) having outliers
Hope this helps!
6 0
2 years ago
What is 170% of 97 tons???
Ede4ka [16]
x=170\% * 97 \\ \\ x= \frac{170}{100} *97 \\ \\ x= \frac{17}{10}*97 \\ \\ x= \frac{1649}{10}=164.9
6 0
2 years ago
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