Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
Step-by-step explanation:
we know that
The roots of the quadratic function (x-intercepts) are
x=-1 and x=5/3
so
we can write the equation of the parabola as
where
a is a coefficient
Remember that
The parabola pass through the point (5,40)
substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a
x=5, y=40
substitute
apply distributive property
see the attached figure to better understand the problem
Answer:
all of them except for compass
Step-by-step explanation:
eeeeerrrr eeeerrr eeeerrrrr
