1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marissa [1.9K]
3 years ago
8

The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand

om variable is just as likely to be larger than its median as it is to be smaller. The mode of a continuous random variable having pdf f(x) is the value of x for which f(x) attains its maximum. Find the median and the mode of X if X is(a) uniformly distributed over (a, b)(b) normal with parameters μ, σ2(c) exponential with parameter λ
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = \mu

c) Exponential with parameter lambda

Median = \frac{ln2}{\lambda }

Mode =0

You might be interested in
Someone please help me with my homework please please help please help me with my homework
densk [106]
C=2x Pi x R so 2x3.14x17.5 = 109.9
5 0
3 years ago
Volunteers at Sam's school use some of the student council's savings for a special project. They buy 8 backpacks for $9 each and
Novay_Z [31]


8 x $9 = $72.00

8 x $3 = $24.00

$72.00 + $24.00 = $96.00

savings changed by $96.00

3 0
3 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0
3 years ago
What is the difference between union set and universal set​
VARVARA [1.3K]

Answer:

Universal set is a set which contains all values

Union of Sets : The joining of two or more sets  .

Step-by-step explanation:

5 0
3 years ago
Multiply 3.76 X.2<br> Show your work
WITCHER [35]

Answer:

7.52

Step-by-step explanation:

  1. Write it out: 3.76 × 2
  2. 3.76 × 2 = 7.52

I hope this helps!

7 0
3 years ago
Other questions:
  • Kalina is choosing a sandwich and a drink for lunch. She can choose between turkey, ham, and vegetarian sandwiches. She chooses
    11·2 answers
  • HURRY!!!! I need help with this asap!!!!!
    9·1 answer
  • Factor using the GCF.<br> 12x + 4
    14·1 answer
  • What is the area of the figure
    15·2 answers
  • 2x - 2(4x-3) = 6 - 6x​
    14·1 answer
  • Is 213 2.3 greater less or equal to
    13·1 answer
  • What is the PE of an object that is 15kg that is 5.0 M above the ground?
    10·1 answer
  • After a history test with 20 questions, the teacher asks his students to write down the number of the questions that was the mos
    14·2 answers
  • PLEASE HURRY THE TEST HAS 5 MINS LEFT I NEED HELP WITH QUESTION 5 ASAP
    12·1 answer
  • I need help finding our the perimeter
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!