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marissa [1.9K]
3 years ago
8

The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand

om variable is just as likely to be larger than its median as it is to be smaller. The mode of a continuous random variable having pdf f(x) is the value of x for which f(x) attains its maximum. Find the median and the mode of X if X is(a) uniformly distributed over (a, b)(b) normal with parameters μ, σ2(c) exponential with parameter λ
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = \mu

c) Exponential with parameter lambda

Median = \frac{ln2}{\lambda }

Mode =0

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This table gives a few (x, y) pairs of a line in the coordinate plane. What is the x-intercept of the line?
PIT_PIT [208]

Answer:

<em>x=-14</em>

Step-by-step explanation:

The x-intercept of a line is the value of x that makes y=0.

A line can be expressed in its slope-intercept form:

y=mx+b

Once determined the equation of the line, the x-intercept can be calculated by setting y=0 and solving for x.

Let's find the slope of the line.

Suppose we know the line passes through two points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Let's pick the first two points of the table (-94,24) (-74,18). The slope is:

\displaystyle m=\frac{18-24}{-74+94}=\frac{-6}{20}=-\frac{3}{10}

The equation of the line is:

\displaystyle y=-\frac{3}{10}x+b

Now use one of the points to find b, for example (-94,24):

\displaystyle 24=-\frac{3}{10}\cdot (-94)+b

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\displaystyle 24=\frac{141}{5}+b

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The complete equation of the line is:

\displaystyle y=-\frac{3}{10}x-\frac{21}{5}

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\displaystyle 0=-\frac{3}{10}x-\frac{21}{5}

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x=-14

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