BC is parallel to DE What is AC?

Mathematics

2 answers:

Olenka [21]3 years ago

6 0

Answer:

the answer is indeed 12

DaniilM [7]3 years ago

3 0

ΔABC ~ ΔADE
AC/AE = AB/AD
AC/(AC+15) = 8/18
18AC = 8(AC+15)
18AC = 8AC + 120
18AC - 8AC = 120
10AC = 120
AC = 120/10
AC = 12

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Which point is 7 units from (–2, 4)?

Serjik [45]

The distance formula:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(-2,4) \\
d=7 \\ \\
7=\sqrt{(x-(-2))^2+(y-4)^2} \\
7=\sqrt{(x+2)^2+(y-4)^2} \ \ \ |^2 \\
49=(x+2)^2+(y-4)^2$
Check which point satisfies the equation:
$(x,y)=(-5,4) \\
49 \stackrel{?}{=} (-5+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} (-3)^2+0^2 \\
49 \stackrel{?}{=} 9 \\
49 \not= 9 \\
doesn't \ satisfy \ the \ equation$

$(x,y)=(-2,3) \\
49 \stackrel{?}{=} (-2+2)^2+(3-4)^2 \\
49 \stackrel{?}{=} 0^2+(-1)^2 \\
49 \stackrel{?}{=} 1 \\
49 \not= 1 \\
doesn't \ satisfy \ the \ equation$

$(x,y)=(5,4) \\
49 \stackrel{?}{=} (5+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} 7^2+0^2 \\
49 \stackrel{?}{=} 49 \\
49=49 \\
satisfies \ the \ equation$

$(x,y)=(9,4) \\
49 \stackrel{?}{=} (9+2)^2+(4-4)^2 \\
49 \stackrel{?}{=} 11^2+0^2 \\
49 \stackrel{?}{=} 121 \\
49 \not= 121 \\
doesn't \ satisfy \ the \ equation$

The answer is C.

3 0

3 years ago

Help! giving brainlest thx!

kipiarov [429]

Answer:

The first one is an Obtuse triangle and the second is an Acute isosceles triangle :)

Step-by-step explanation:

Hope this helped!

6 0

3 years ago

Read 2 more answers

Represent the following with an equation.