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2 years ago

(I NEED HELP ASAP PLS I HAVE A TEST)

Mathematics

2 answers:

IceJOKER [234]2 years ago

8 0

Answer:

I think its liza

Step-by-step explanation:

Alexandra [31]2 years ago

3 0

Answer:

Max

Step-by-step explanation:

Max percentage improvement in the first exam = $(\frac{6}{20}$ × $100)$ %

= $\frac{600}{20}$ %

= $30$ %

Maria percentage improvement in the first exam = $(\frac{30}{90}$ × $100)$ %

= $\frac{3000}{90}$

= $33.3333333333$ Round $33.33$ %

Hence, 30% < 33.33%

Therefore, Max showed less improvement.

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The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches What is the height of the tr

ExtremeBDS [4]

The height of the triangular base of the pyramid is calculated through the equation,
h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of x is 30°. Substituting,
h = (cos 30°)(18 in)
h = 15.59 in
Thus, the height of the base is approximately 15.59 inches.

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3 years ago

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3 years ago

What fraction of the months in the year have 30 days?

weeeeeb [17]

Answer:

4/12 which reduces to 1/3

Step-by-step explanation:

4 out of 12 months have 30 days.

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3 years ago

50 POINTS!!!! PLEASE HELP!!!!!

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Answer:

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3 years ago

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Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2

evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

$\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}$

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

$\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}$

Step # 1 : Swap the first and second matrix rows,

$\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}$

Step # 2 : Cancel leading coefficient in row 2 through $R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1$ ,

$\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}$

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

$\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}$

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0

3 years ago