Let , side lawn is a.
Area of boundary is :
Now, total cost is given by :
Area left is :
Price to empty space with turfs is :
Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
Answer:
see explanation
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
Answer:
Step-by-step explanation:
Given that,
The dimensions of a rectangular block = 4 cm x 2 cm x 1.5 cm
Mass, m = 93.6 g
We need to find the density of steel. We know that the density of an object is equal to the mass divided by volume. So,
So, the density of the steel is .