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3 years ago

Rearrange the equation to isolate h: A= 1/2bh

1 answer:

3 0

First we will multiply both sides by 2 to eliminate 1/2 from h.

2 x A = 1/2bh x 2
2A = bh

Now we divide both side by b to eliminate b from h.

2A / b = bh/b
2A/b = h

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What is the answer to (−2)³

svetlana [45]

(−2)³ = (-2)(-2)(-2)

Note that:

two negative numbers multiplied together results in a positive

one negative and one positive number multiplied results in a negative

Multiply:

(-2)(-2) = 4

4(-2) = -8

-8 is your answer

hope this helps

4 0

3 years ago

Read 2 more answers

Which of the following shows the factors of 9x2 + 3x - 2?

Paha777 [63]

C. (3x+1)(3x-2) 3x times 3x= 9x^2 and 3x times -1= -3x
2 times 3x= 6x and 2 times -1= -2
9x^2- 3x+6x-2
9x^2+3x-2
Hope I explain this more clearly for you.

4 0

3 years ago

Is there a way to find figure out a function with just the X & Y intercepts. I know there are convertors to find the X &

AlladinOne [14]

Answer:

Step-by-step explanation:

yes, since that are 2 points:

y-int is (0, y)

x-int is (x, 0)

since you need only two points for a function with no restrictions, we can use y and x intercepts as points

3 0

3 years ago

2.79 ? 2.790<br> Are they equal or which one is greater

tatiyna

Answer:

they are equal

Step-by-step explanation:

because you can add how many zeroes after 2.79 but it is going to still be equal.

7 0

2 years ago

Solve sin x - (3sin x-1) = 0

soldi70 [24.7K]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}$

Step-by-step explanation:

$\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}$

$\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.$

$\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}$

$\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi$

3 0

2 years ago