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-Dominant- [34]
4 years ago
6

(-36 4/9) - (-10 2/9) - (18 2/9) solve

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
6 0

Convert 36 4/9 to an improper fraction. Use this rule: a b/c = ac + b/c

-36 × 9 + 4/9 - (-10 2/9) - 18 2/9

Simplify 36 × 9 to 324

- 324 + 4/9 - (-10 2/9) - 18 2/9

Simplify 324 + 4 to 328

- 328/9 - (-10 2/9) - 18 2/9

Convert 10 2/9 to an improper fraction. Use this rule: a b/c = ac + b/c.

-328/9 - (- 10 × 9 + 2/9) - 18 2/9

Simplify 10 × 9 to 90

-328/9 - (- 90 + 2/9) - 18 2/9

Simplify 90 + 2 to 92

- 328/9 - (-92/9) - 18 2/9

Convert 18 2/9 to an improper fraction. Use this rule: a b/c = ac + b/c.

-328/9 - (- 92/9) - 18 × 9 + 2/9

Simplify 18 × 9 to 162

-328/9 - (- 92/2) - 162 + 2/9

Simplify 162 + 2 to 164

-328/9 - (- 92/9) - 164/9

Simplify brackets

-328/9 + 92/9 - 164/9

Join the denominators

-328 + 92 - 164/9

Simplify

-400/9

Convert to a mixed fraction

-44\frac{4}{9}

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the sum of areas of two circles is 80 square meters find the lencgh of radius of each circles if one of them is twice as larger
klemol [59]
Area of a cirlce=πr²
we have two radius:2r and  r
area of the cirlce₁ + area of the circle₂=80 m²
area of the circle₁=π(2r)²
area of the circle₂=πr²
Then, we can suggest this quation:

π(2r)²+πr²=80

4πr²+πr²=80
π(4r²+r²)=80
π(5r²)=80
5πr²=80
r²=80/5π
r=√(80/5π)≈2.26

radius of the largest cirlce=2r=2(2.26)=4.51

Answer: the radius of the largest circle is 4.51 m
6 0
4 years ago
Read 2 more answers
What principal invested at 8% compounded continuously for 4 years will yield $1190?
zhuklara [117]
For continuously compounded interest:

Amount = Principle * e^(rate * time)

A rate of 8% converted to a decimal value: r=0.08
With time t=4
and amount 1190

Plug all these values in,

1190 = Principle * e^(0.08 * 4)

And use your calculator to solve for the principle.
Maybe we'll call it P to make things easier.

1190 = P * e^(0.08 * 4)
1190 = P * 1.377

The principle is being multiplied by this 1.377,
divide by 1.377 to undo the multiplication.

864.11735 = P

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The answer to that algebra 2 equation
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