1:0.05
I think this is the answer
Answer:
x<1 x>-7
Step-by-step explanation:
|x+3|<4
We know x+3<4 and x+3>−4
x+3<4 (Condition 1)
x+3−3<4−3 (Subtract 3 from both sides)
x<1
x+3>−4 (Condition 2)
x+3−3>−4−3 (Subtract 3 from both sides)
x>−7
Answer:
x<1 and x>−7
Answer:
<em>x² - 28x√x + 294x - 1372√x + 2404 </em>
Step-by-step explanation:
f(x) =
+ 3
g(x) = x - 7
h(x) = √x
f(g(h(x))) - ?
g(h(x)) = √x - 7
f(g(h(x))) =
+ 3 = ( √x - 7 )² × ( √x - 7 )² + 3 =
= (x - 14√x + 49)(x - 14√x + 49) + 3 =
= x² - 14x√x + 49x - 14x√x + 196x - 686√x + 49x - 686√x + 2401 + 3 =
= <em>x² - 28x√x + 294x - 1372√x + 2404</em>
<span>6/3+(-1/3)
</span><span>= 6/3-1/3
= 5/3
= 1 2/3</span>