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Y_Kistochka [10]
3 years ago
11

PLAESE HELP

Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Hey there!

I took the test, and I can confirm that B. Line 2 only is the CORRECT answer

xXxGolferGirlxXx

ankoles [38]3 years ago
4 0

Ok well let's start with line 1:

(x + 2)(x - 3) = x^2 - x - 6 (this works so far)
(x + 0.5)^2 - 6.25 = x^2 + x + 0.25 - 6.25
= x^2 + x - 6 (this is not equal to x^2 - x - 6 so Line 1 is not an answer)

Now for line 2:


(x + 1)(x - 2) = x^2 - x - 2 (this works so far)
(x - 0.5)^2 - 2.25 = x^2 - x + 0.25 - 2.25
= x^2 - x - 2 (this also works)
Therefor Line 2 only is the answer
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Select the correct answer.<br> Solve this inequality for x: -46 − 8x &gt; 22.
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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

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