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horrorfan [7]
3 years ago
5

Step by step on how to get j/-2+7=-12

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

38

Step-by-step explanation:

(j/-2) + 7 = -12

I move the 7 over by subtracting since its a positive 7

j/-2 = -19

now multiply each side by -2 to cancel out the denominator

j = 38

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Which statement is true of every plane in three-dimensional space?
leonid [27]

Answer:

option A is correct.(Every plane must have three intercepts.)

Step-by-step explanation:

" Three-dimensional space (also: 3-space or, rarely, tri-dimensional space) is a geometric setting in which three values (called parameters) are required to determine the position of an element (i.e., point). This is the informal meaning of the term dimension "

The intercept form of the equation of plane in 3-D is given by:

\dfrac{x}{l}+\dfrac{y}{m}+\dfrac{z}{n}=1

Where l,m,n are intercepts of x,y,z axes and a plane respectively.

Hence, we require all the three intercepts of a every plane.

Hence, option A is correct.

4 0
3 years ago
Read 2 more answers
PLZ HELP!!! WILL GIVE HIGHEST POINTS IF THE ANSWER IS CORRECT!!!
antoniya [11.8K]

Answer:

ab multiplied by ( A -B)

Step-by-step explanation:

7 0
3 years ago
If (-2,3), 3x-2ky+4=0 find the value of k
ipn [44]
Answer: k = -1/3

Step-by-Step Explanation:

=> 3x - 2ky + 4 = 0
Value of ‘x’ = -2
Value of ‘y’ = 3

Substitute values of ‘x’ and ‘y’ :-
=> 3x - 2ky + 4 = 0
= 3(-2) - 2k(3) + 4 = 0
= -6 - 6k + 4 = 0
= -6k = 6 - 4
= -6k = 2
= k = 2/-6
=> k = -2/6 = -1/3

Therefore, k = -1/3
8 0
2 years ago
Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t
Anika [276]

Answer:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

Step-by-step explanation:

Given

\int\limits {\frac{x}{x^4 + 16}} \, dx

Required

Solve

Let

u = \frac{x^2}{4}

Differentiate

du = 2 * \frac{x^{2-1}}{4}\ dx

du = 2 * \frac{x}{4}\ dx

du = \frac{x}{2}\ dx

Make dx the subject

dx = \frac{2}{x}\ du

The given integral becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

Recall that: u = \frac{x^2}{4}

Make x^2 the subject

x^2= 4u

Square both sides

x^4= (4u)^2

x^4= 16u^2

Substitute 16u^2 for x^4 in \int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du

Simplify

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

In standard integration

\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)

So, the expression becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)

Recall that: u = \frac{x^2}{4}

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

4 0
3 years ago
Help cant use calcultor??? 437 + 356 = ?
Zinaida [17]
437 + 356= 793

ANSWER: 793

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
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