yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows;
From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score
(x-μ)/σ
we shall have:
(x-5000)/50=-2.57
solving for x we get:
x-5000=-128.5
x=-128.5+5000
x=4871.50
1,10 and 2,5,
those are the pairs
The graph is a straight line graph with a slope of -1/2
Equation of a line in point-slope form
The equation of a line in point slope form is expressed as:
y - y₁ = m(x - x₁)
Given the following parameters
Point = (-2, 3)
Slope = -1/2
Substitute the given parameters into the formula
y-3 = -1/2(x-(-2))
y-3 = -1/2(x+2)
Write in slope-intercept form
2(y-3) = -(x+2)
2y-2(3) = -x -2
2y - 6 = -x -2
2y = -x + 4
y = -1/2x + 2
The graph of the equation is as shown below
Learn more on equation of a line here: brainly.com/question/18831322
#SPJ1
-7a + 5a < -(7-a) -(2a +1) Turns to
-7a +5a < -7 +a -2a -1 Which turns to
-2a < -1a -8 Which turns to
-1a < -8 Which turns to
1a > 8
:)