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3 years ago

7(square root 14) divided by (square root 7)

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

The question given above will require a good understanding of surd operation in order to arrive at the best answer

$\frac{7\sqrt{14} }{\sqrt{7}} = 7\sqrt{2}$

To solve this problem, we shall simply rationalise the denominator. This can be obtained as illustrated below:

$\frac{7\sqrt{14}}{\sqrt{7}}\\\\Rationalise\\\\\frac{7\sqrt{14}}{\sqrt{7}} * \frac{\sqrt{7} }{\sqrt{7}}\\\\\frac{7\sqrt{14*7}}{\sqrt{7*7}}\\\\\frac{7\sqrt{98}}{\sqrt{49}}\\\\\frac{7\sqrt{98}}{7}\\\\\sqrt{98}\\\\\sqrt{98} = \sqrt{49*2} \\\sqrt{98} = \sqrt{49} * \sqrt{2} \\\sqrt{98} = 7\sqrt{2} \\\\Thus, \\\\\frac{7\sqrt{14}}{\sqrt{7}} = 7\sqrt{2}$

Therefore, from the calculations made above, the solution to the question is 7√2

Learn more: brainly.com/question/11225829

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Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

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3 years ago

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3 years ago

Read 2 more answers

A fish story: The mean length of one-year-old spotted flounder, in millimeters, is 127 with standard deviation of 22, and the me

pishuonlain [190]

Answer:

The z-score for this length is of 1.27.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

One-year-old flounder:

Mean of 127 with standard deviation of 22, which means that $\mu = 127, \sigma = 22$