That is (t^9)^-8
= t^(9*-8)
= t^-72 or 1 / t^72
For properties of logarithm we have the following:
loga (x ^ b) = b * loga (x)
Therefore, following this property we have for this case:
log3 (x ^ 9) = 9log3 (x)
Answer:
the power property to rewrite log3x9 is:
B) 9log3x
You first substract 18 from both sides so you get
10x<-20 you then divide by 10 so the answer is
x<-2
Answer:
c is the answer
Step-by-step explanation:
You would round both numbers and subtract. For example 189 can round to 200 and 643 would round to 600. Now just subtract, 600-200=400
