We could say that dimes = x and quarters = 60 -x
Then we use the value of the coins
10(x) + 25(60-x) = 945
I did 945 because I am doing this in cents not dollars but the answer would still work because it is asking for the amount of coins.
10x + 1500 - 25x = 945
-15x = -555
x = 37
Dimes = x = 37
Quarters = 60 - x = 60 -37 = 23
<em><u> </u></em><em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
y = x + 3
Step-by-step explanation:
y = mx + b
m is the slope
b is the y intercept
if m = 1 and b = 3 then
y = x + 3
Answer:
The answer is "
"
Step-by-step explanation:
In point a:
The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.
They can now pick 1 genin from a certain matter of national with the value:

They can pick 1 Chunin form of the matter of national with the value:

They have the option to pick 1 join from of the country team with such a probability: 
And we can make the country teams:
different forms. Its chances of choosing a team full in the process described also are:
In point b:
In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).
Its likelihood that even a specific nation team ninja would be chosen is now: 
Its odds of choosing the same rank ninja in such a different country team are: 
The likelihood of choosing the same level Ninja from the residual matter of national is:
Therefore, all 3 selected ninjas are likely the same grade: 
Answer:
Step-by-step explanation:
Unless we set x^2 + 8x + 15 equal to zero, we don't have an equation to be solved. I will assume that the problem is actually x^2 + 8x + 15 = 0.
The coefficients of this quadratic are {1, 8, 15}, and so the "discriminant" b^2 - 4ac is (8)^2 - 4(1)(15), or 4. Because the discriminant is positive, we know that there are two real, unequal roots.
Continuing with the quadratic formula and knowing that the discriminant is 4, we get:
-8 ± √4 -8 ± 2
x = ---------------- = --------------- , or x = -2 ± 1: x = -3 and x = -5
2 2