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LekaFEV [45]
3 years ago
8

What is 4 to the 60th power

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0
12,960,000 that is the answer
brilliants [131]3 years ago
6 0
What is 4th to the 60th piwer
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Tpy6a [65]
What are we supposed to be basing this off of? is there no additional information?
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Which figures can be precisely defined by using only undefined terms? Select three options.
love history [14]

This is a pretty bad question but I think the answer they're looking for is

angle

circle

line segment

We define arcs in terms of circles and parallel lines in terms of lines (though not necessarily line segments, so this is a bit of a judgement call).

8 0
3 years ago
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Please answer this also I need help
yKpoI14uk [10]

Answer: 2/2

Step-by-step explanation:

6 x 2/2 =6

7 0
3 years ago
Find the product. (r s)2 r² 2rs s r² 2rs s² r² 2rs 2s².
sveta [45]

The product of the given expression is \rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs.

Given

The product of \rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2.

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of \rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2 is given by;

\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2\\\\(2r^3 + 2r^2s) + 2rs + 2rs + 2rs + s^2r^2 + sr^2 + 2s^2\\\\2r^3+ 2r^2s + 6rs + s^2r^2 + sr^2+ 2s^2

\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs

Hence, the product of the given expression is \rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs.

To know more about Multiplication click the link given below.

brainly.com/question/19943359

6 0
2 years ago
What is the answer when you evaluate m + p - p2 ÷ 6; use m = 5 and p = 6 ?
Tanya [424]

Answer:

5

Step-by-step explanation:

m + p - p^2 ÷ 6

Let m = 5 and p=6

5 + 6 - 6^2 ÷ 6

Exponents first

5 + 6 - 36 ÷ 6

Then divide

5 + 6 - 6

Then add and subtract from left to right

11-6

5

3 0
2 years ago
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