C since that's the only triangle where A^2+B^2=C^2 (36+64=100).
Question:
You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?
Answer: 4 miles
Step-by-step explanation:
Let distance between start to first checkpoint = x
First checkpoint to second checkpoint = 2/5 of x
Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)
Distance of start to checkpoint 2 = (1/4 of start to finish)
If start to checkpoint 2 = 1/4 of start to finish
Then,
Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)
Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish
Entire race = 40 miles = distance from start to finish
1/ 10 of 40
= ( 1/10) × 40
= 4 miles
For this case, what we must do is solve the following system of equations:
tan (50) = h / x
tan (40) = h / (x + 50)
Solving the system we have:
(x + 50) * tan (40) = h
(x) * tan (50) = h
Matching:
(x + 50) * tan (40) = (x) * tan (50)
Rewriting:
x (tan (50) - tan (40)) = 50 * tan (40)
x = 50 * tan (40) / (tan (50) - tan (40))
x = 118.9692621
Substituting:
h = (x) * tan (50)
h = (118.9692621) * tan (50)
h = 141.7820455
Answer:
The height of the building is:
h = 141.7820455 ft
<u>Corrected question :</u>
Solve the equation. Write your answer as an integer or simplified fraction.
<u>Required Solution :</u>
The given equation,
★ Multiplying -7 into (n - 2),
>> 8n - 7 × (n - 2) = 18
>> 8n - 7n + 14 = 18
★ On substracting 7n from 8n we gets,
>> n + 14 = 18
★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),
>> n = 18 - 14
>> n = 14
★ Therefore,
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