Answer:
The volume of the container is
Step-by-step explanation:
we know that
The volume of the figure is equal to
where
B is the area of the base
h is the height of the figure
Let
Find the area of the base B
substitute
66 2/3 as a mixed number or 200/3 as an improper fraction.
That would be 66 2/3.
0.6 recurring is 2/3.
2*3+4=10
5+2x2=9
4-3+2=3
4*3+2=14
20-4x3+6=14
16-30/2+11=12
24/6*5=20
15/5+2=5
2+2*9-5=15
12-3+4*2=1
12/3+3*4=16
9-6/3=7
16-3*4=4
36/4/9=1
The last one is yours
