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2 years ago

Write the rule for the nth term of geometric sequence a1=6 and r=3

Mathematics

1 answer:

pychu [463]2 years ago

6 0

Step-by-step explanation:

Hey there!

Given;

a1 = 6

and r = 3

Then;

Let's see, we have a1 "first term" and r "common ratio". So, firstly use the formula.

$nth \: term \: of \: geometric \: sries = {a}^{} . {r}^{n - 1}$

Now, keep all values.

$nth = 6 \times {3}^{n - 1}$

So, it becomes like this.

Therefore, the rule is nth= 6*3^n-1.

Hope it helps!

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i am begging for help. all of my points for the first to answer. The volume of a sphere is 3/4 x pi cm^3. what is the radios of

horsena [70]

volume of a sphere = 4/3 *pi * r^3

3/4 * pi = 4/3 *pi * r^3

divide each side by pi

3/4 = 4/3 * r^3

multiply each side by 3/4

3/4 * 3/4 = r^3

9/16 = r^3

take the cube root of each side

r = (9/16) ^ (1/3)

3 0

3 years ago

In the following diagram lines m are n parallel the measures of AEB, BAE and CED are shown what is the measure of EBF

guapka [62]

Answer:

∠ EBF = 98°

Step-by-step explanation:

(3x - 15) and (2x + 10) are vertically opposite angles and are congruent, then

3x - 15 = 2x + 10 ( subtract 2x from both sides )

x - 15 = 10 ( add 15 to both sides )

x = 25

3x - 15 = 3(25) - 15 = 75 - 15 = 60°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ EBF is an exterior angle of the triangle , then

∠ EBF = 60° + 38° = 98°

8 0

2 years ago

What two equivalent ratios for 30 to 6

alexgriva [62]

Two equivalent ratios for 30 to 6 can be 15 to 3 or 45 to 9

5 0

2 years ago

Drag values to complete each equation.

Alex777 [14]

Answer:

1. A. 1

2. D. $17^9$

Step-by-step explanation:

Properties used:

Power of a Power Property
Product Property
Quotient Property
Zero Exponent Property

1. First, let's deal with the numerator.

$(17^3)^6$ can be turned into $17^1^8$ by using the Power of a Power Property.

And then use the Product Property, $(17^1^8)(17^-^1^0) = 17^8$

So now, our fraction is this: $\frac{17^8}{17^8}$

All number over itself in a fraction is equal to 1. But you can also do this the mathmatic way using the Quotient Property: $\frac{a^m}{a^n} = a^m^-^n$ or $\frac{1}{a^(^n^-^m^)}$ . Which then you plug the numbers in: $\frac{17^8}{17^8} = 17^8^-^8 = 17^0$ . And since we know that in Zero Exponent Property: $a^0 = 1$ , we can see that $17^0 = 1$ . So either way, we get 1.