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Paha777 [63]
2 years ago
13

Write the rule for the nth term of geometric sequence a1=6 and r=3

Mathematics
1 answer:
pychu [463]2 years ago
6 0

Step-by-step explanation:

Hey there!

Given;

a1 = 6

and r = 3

Then;

Let's see, we have a1 "first term" and r "common ratio". So, firstly use the formula.

nth \: term \: of \: geometric \: sries =  {a}^{} . {r}^{n - 1}

Now, keep all values.

nth = 6 \times  {3}^{n - 1}

So, it becomes like this.

Therefore, the rule is nth= 6*3^n-1.

<em>Hope</em><em> </em><em>it </em><em>helps</em><em>!</em>

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dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

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  • Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.

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Step-by-step explanation:

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F(x) = x2 – 2x - 8
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see the attached figure

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see the attached figure to better understand the problem

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