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3 years ago

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Consider a machine that exchange quarters for dollar bills. Inserting one dollar bill returns four quarters and you may insert u

p to five one dollar bills at a time. Is 7 a possible input for the relation this change machine represents ?

1 answer:

Afina-wow [57]3 years ago

8 0

No because it says you can only insert up to 5 Dollar Bills unless you put them in one at a time.

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Order the following number from smallest to largest. <br><br>25, 10, -15, 0, -5

blondinia [14]

Answer:

-15, -5, 0, 10, 25

Step-by-step explanation:

The highest negative integer would be the smallest number, the the largest positive number would be the largest.

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Look at the screenshot

BaLLatris [955]

Answer:66.6 but if round 67%

Step-by-step explanation:

Because 52 ÷78 =66.6

So it's 67%

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Yes this is correct

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On a coordinate grid, 1 square unit equals 14 square mile. A rectangular walking path has vertices at (−4, 5) (1, 5), (−4, -5) a

AfilCa [17]

Answer:

126 square miles

Step-by-step explanation:

So I just draw a grid and mark the thingies (sorry my math vocabulary is not very good)

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Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w

pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, the circle is centered at the origin, hence $(x_0, y_0) = (0,0)$ .

The circle contains the point (-13,0), hence the radius is found as follows:

$x^2 + y^2 = r^2$

$(-13)^2 + 0^2 = t^2$

$r^2 = 169$

Hence the equation is:

$x^2 + y^2 = 169$

Then, we test if point (√5, 12) is on the circle:

$x^2 + y^2 = 169$

$(\sqrt{5})^2 + 12^2 = 169$

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

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