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Minchanka [31]
2 years ago
15

Prove that :- Cos3A-cosA/sin3A-sinA+cos2A-cos4A/sin4A-sin2A=sinA/cos2Acos3A

Mathematics
1 answer:
ad-work [718]2 years ago
8 0
\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1

R_s=\dfrac{\sin A}{\cos A\cos^4A}=\dfrac{\sin A}{\cos A}\cdot\dfrac{1}{\cos^4A}=\tan A\cdot\dfrac{1}{\cos^4A}=\dfrac{\tan A}{\cos^4A}


\boxed{L_s\neq R_s}
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F(x) = x^2 + 1 is limited to (0, 1, 2, 3), what is the maximum love you all of the range?
wlad13 [49]

Answer:

2

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f(x)=x^2+1

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4 0
3 years ago
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

(printers after first slot = 10; total defective printers = 2)

Then, total probability =\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}

7 0
3 years ago
1/3x+4=x-2<br><br><br> SHOW WORK
Len [333]
X= -3
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8 0
3 years ago
Triangle A B C has centroid G. Lines are drawn from each point through the centroid to the midpoint of the opposite side to form
d1i1m1o1n [39]

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The length of GF is 254 units.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

Since a centroid of a triangle divides the median into a ratio of 2:1. Therefore, the ratio of AG: DG is,

AG / DG = 2/1

(19x+14)/(9x+20) = 2/1

19x + 14 = 18x + 40

19x - 18x = 40 - 14

x = 26

Assuming the triangle is an equilateral triangle, therefore, the length of GF will be,

GF = DG = 9x+20

GF = DG = 9(26) + 20

GF = 254 units

Hence, the length of GF is 254 units.

Learn more about Triangle:

brainly.com/question/2773823

#SPJ1

6 0
2 years ago
Algebra 2 help!! Find the value of k
Oksana_A [137]

13  By the factor theorem, if the function is divisible by x - 3 then f(3) = 0. So we have:-

2(3)^3 + k(3)^2 + 7(3) - 3 = 0

9k = 3 - 21 - 54 = -72

k =  -72/9 =  -8 answer

14.   Similarly ,   f(-4) = 0 , so we have:-

(-4)^3 + 9(-4)^2 + k(-4) - 12 = 0

-64 + 144 - 4k - 12 = 0

4k = -64 + 144 - 12 = 68

k = 68/4

k = 17   answer

4 0
3 years ago
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