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Minchanka [31]
3 years ago
15

Prove that :- Cos3A-cosA/sin3A-sinA+cos2A-cos4A/sin4A-sin2A=sinA/cos2Acos3A

Mathematics
1 answer:
ad-work [718]3 years ago
8 0
\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1

R_s=\dfrac{\sin A}{\cos A\cos^4A}=\dfrac{\sin A}{\cos A}\cdot\dfrac{1}{\cos^4A}=\tan A\cdot\dfrac{1}{\cos^4A}=\dfrac{\tan A}{\cos^4A}


\boxed{L_s\neq R_s}
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<u>Answer: </u>

Expression x + 2my + z represents cost of order where x, y, z are cost of small , medium and large drinks (in dollars) respectively.

<u>Solution: </u>

Given that  

Juan’s family ordered a small drink and m medium drinks.

Alex family ordered m medium drinks and a large drink.

Need to write an algebraic expression which shows total cost of both order in dollars.

Let’s assume cost of one small drink = x

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So now cost of order of Juan’s family is equal to cost of 1 small drink + cost of m medium drinks = 1 \times x + m \times y

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Step-by-step explanation:

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Answer:

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