They give us 2 pieces to the puzzle. Both are positive numbers...x and y.
1.) 1 number is 1 less than twice another number. (x = 2y -1)...and
2.) the sum of their squares is 106. (x^2 + y^2 = 106).
substitute the value for x into the second equation.
(2y-1)^2 + y^2 = 106
(2y-1) (2y-1) + y^2 = 106 (use distributive property)
4y^2 - 2y - 2y + 1 + y^2 = 106 (subtract 106 from both sides)
4y^2 - 2y - 2y + 1 + y^2 - 106 = 106 - 106 (combine like terms)
5y^2 - 4y - 105 = 0 (factor)
(y-5) (5y-21) = 0 (set to 0)
y - 5 = 0
y = 5
substitute the 5 into the equation for y (x = 2(5) - 1)
x = 9 if we square 9, we get 81.
subtracted from 106 we have 25...the square root of 25 is 5.
our answers are 5 and 9.
Liz wants to find the quotient of 63 and 0.15. what is the first step she should take?
Answer:
→(Well First 63 ÷ 0.15 = 420) ←
A: divide 63 and 0.15 by 10 Would be my Answer
To add two decimal numbers, first check if they have the same number of digits to the right of the decimal point. If they don't, add zeros to the right of one of the numbers until they do. Then, write one number on top of the other, lining up the decimal points vertically.
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Step-by-step explanation:
