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Amiraneli [1.4K]
2 years ago
7

Solve the square root of 2x-5=x-4​

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
8 0
Answer:

Simplifying
2x + -5 = x + -4

Reorder the terms:
-5 + 2x = x + -4

Reorder the terms:
-5 + 2x = -4 + x

Solving
-5 + 2x = -4 + x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
-5 + 2x + -1x = -4 + x + -1x

Combine like terms: 2x + -1x = 1x
-5 + 1x = -4 + x + -1x

Combine like terms: x + -1x = 0
-5 + 1x = -4 + 0
-5 + 1x = -4

Add '5' to each side of the equation.
-5 + 5 + 1x = -4 + 5

Combine like terms: -5 + 5 = 0
0 + 1x = -4 + 5
1x = -4 + 5

Combine like terms: -4 + 5 = 1
1x = 1

Divide each side by '1'.
x = 1

Simplifying
x = 1
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Solve quadratic formulax^2-4x+3=0
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The general formula for a equation of the form:

ax^2+bx+c=0

is:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}

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8 0
1 year ago
Can anyone help me on this question please.​
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The answer is 72.
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