79 divided by 10= 7
7x10= 70
79-70=9
Put a 0 beside the nine
Put the decimal beside the 7
10x9=90
90-90=0
Ur answer is 7.9
Answer:

Step-by-step explanation:
we know that
The area of the polygon is equal to the area of a square plus the area of four congruent triangles
so
![A=b^2+4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=A%3Db%5E2%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
where

substitute
![A=8^2+4[\frac{1}{2}(8)(4)]](https://tex.z-dn.net/?f=A%3D8%5E2%2B4%5B%5Cfrac%7B1%7D%7B2%7D%288%29%284%29%5D)

Answer:
where do you see jl there is only jk and kl
Step-by-step explanation:
Answer:
63
Step-by-step explanation:

divide, 27 ÷ 3
you'll get 9, so
x = 9
Next part
5y = 35
divide both sides by 5 to isolate y,
5y ÷ 5 = 35 ÷ 5
=
y = 7
So
x = 9 and y = 7
Then let's add the numbers to our equation ( x × y)
9 × 7
=
63
5y - 3y + 12
Because there is not a common factor between the three terms in it's current state, we must simplify.
2y + 12
Now, we can simplify using the distributive property.
Factor 2.
<h3>2(y + 6) is the factored form of the original expression.</h3>