Answer:
seeps in to ground water . what is the life or nuclear waste? it's a lot longer than the storage places will last.
Explanation:
Answer:
The tropical rainforest.
Explanation:
Oceania is a region that comprises the territories of Australia, New Zealand, New Guinea, and many island groups in the Pacific Ocean. Most of the islands in Oceania tend to have a very similar climate, with only Australia sticking out as having multiple different types of climates and ecosystems. The ecosystem that is the most abundant with plants and animals is the tropical rainforest.
Tree kangaroos, frogs, birds, ferns, and tall and dense trees, are typical for the tropical rainforest. This ecosystem can be found in the northeastern part of Australia and across New Guinea. This ecosystem can also be found in most of the island groups in Oceania, though they lack some of the organisms mentioned. The characteristics of the tropical rainforest are constantly high temperatures, high levels of precipitation and humidity, and very high biodiversity.
Answer:
What is the model anyways?
Explanation:
Answer:
![\mathbf{Q_p =682 \ \ ft^3/s}](https://tex.z-dn.net/?f=%5Cmathbf%7BQ_p%20%20%3D682%20%5C%20%5C%20%20ft%5E3%2Fs%7D)
Explanation:
Given that:
Area = 475 acres
The length of the channel (L) = 6870 feet
The average water shield slope (S) = 100 feet/mile
Since; 1 mile = 5280 feet
Burst duration D = 15 min
∴
100 feet/mile = 100/5280
The average water shield slope (S) = 5/264
Using hydrograph method:
The time of concentration ![t_c = 0.0078L^{0.77} S^{-0.385}](https://tex.z-dn.net/?f=t_c%20%3D%200.0078L%5E%7B0.77%7D%20S%5E%7B-0.385%7D)
where;
L = 6870
S = 5/264
![t_c = 0.0078(6870)^{0.77} (\dfrac{5}{264})^{-0.385}](https://tex.z-dn.net/?f=t_c%20%3D%200.0078%286870%29%5E%7B0.77%7D%20%28%5Cdfrac%7B5%7D%7B264%7D%29%5E%7B-0.385%7D)
min
Since 60 min = 1 hour
32.34 min will be (32.34*1)/60
= 0.539 hour
Lag time ![T_l = 0.67\times t_c](https://tex.z-dn.net/?f=T_l%20%3D%200.67%5Ctimes%20t_c)
![T_l = 0.67\times 32.34](https://tex.z-dn.net/?f=T_l%20%3D%200.67%5Ctimes%2032.34)
![T_l = 21.6678\ min](https://tex.z-dn.net/?f=T_l%20%3D%2021.6678%5C%20min)
The time to peak i.e
![T_p = \dfrac{D}{2}+ T_L \\ \\ T_p = \dfrac{15}{2}+ 21.6678 \\ \\ T_p = 29.168 \ min](https://tex.z-dn.net/?f=T_p%20%3D%20%5Cdfrac%7BD%7D%7B2%7D%2B%20T_L%20%5C%5C%20%5C%5C%20%20T_p%20%3D%20%5Cdfrac%7B15%7D%7B2%7D%2B%2021.6678%20%5C%5C%20%5C%5C%20%20T_p%20%3D%2029.168%20%5C%20min)
![T_r = \dfrac{T_p}{5.5} \\ \\ T_r = \dfrac{29.1678}{5.5} \\ \\ T_r = 5.30 \ min](https://tex.z-dn.net/?f=T_r%20%3D%20%5Cdfrac%7BT_p%7D%7B5.5%7D%20%5C%5C%20%5C%5C%20%20T_r%20%3D%20%5Cdfrac%7B29.1678%7D%7B5.5%7D%20%5C%5C%20%5C%5C%20T_r%20%3D%205.30%20%5C%20min)
Since D = 15 min is not equal to
, then we hydrograph apart from
duration lag time.
Then;
![T_p \ ' = T_p + \dfrac{D-t_r}{4} \\ \\ T_p \ ' = 29.168 + \dfrac{15-5.30}{4} \\ \\ T_p \ ' = 31.593](https://tex.z-dn.net/?f=T_p%20%5C%20%27%20%3D%20T_p%20%2B%20%5Cdfrac%7BD-t_r%7D%7B4%7D%20%5C%5C%20%5C%5C%20T_p%20%5C%20%27%20%3D%2029.168%20%2B%20%5Cdfrac%7B15-5.30%7D%7B4%7D%20%5C%5C%20%5C%5C%20T_p%20%5C%20%27%20%3D%2031.593)
Now, we need to determine the peak discharge
by using the formula:
![Q_p = \dfrac{484 \times A}{T_p \ '}](https://tex.z-dn.net/?f=Q_p%20%20%3D%20%5Cdfrac%7B484%20%5Ctimes%20A%7D%7BT_p%20%5C%20%27%7D)
where
484 = peak factor
Recall that A = 475 acres, to miles, we have:
A = 0.7422 mile²
![T_p \ ' = 31.593/60](https://tex.z-dn.net/?f=T_p%20%5C%20%27%20%3D%2031.593%2F60)
∴
![Q_p = \dfrac{484 \times 0.7422}{\dfrac{31.593}{60}}](https://tex.z-dn.net/?f=Q_p%20%20%3D%20%5Cdfrac%7B484%20%5Ctimes%200.7422%7D%7B%5Cdfrac%7B31.593%7D%7B60%7D%7D)
![\mathbf{Q_p =682 \ \ ft^3/s}](https://tex.z-dn.net/?f=%5Cmathbf%7BQ_p%20%20%3D682%20%5C%20%5C%20%20ft%5E3%2Fs%7D)
nucleus
Known as the cell's “command center,” the nucleus is a large organelle that stores the cell's DNA (deoxyribonucleic acid).