Okay. so I'm gonna assume you know what factor out means--were gonna take out 5/6. what we need to know is, how does that affect our ending number 2/3? well, we're gonna have 5/6 times some stuff first off, right?
5/6 ( )
so what's in the parenthesis? well, if we distribute in our mind, S would just have to be by itself for it to work out. so we have
5/6 ( s )
but what about 2/3? well, if we're multiplying everything on the inside by 5/6, how can be get it to cancel and leave 2/3 alone? we could divide 2/3 by 5/6, right?
5/6 ( s + (2/3) / (5/6) )
now, when we distribute our 5/6, we'll have just 2/3 at the end. now let's simplify that end term so it looks a little better. if we divide by a fracion, that's the same as multiplying by the flipped version, so let's do that.
2/3 / 5/6 = 2/3 × 6/5 = 2 (6) / 5 (3) = 12/15
we can reduce 12/15 by dividing the top and bottom by three.
= 4/5
so our final answer would be:
5/6 [S + 4/5] you can redistribute to make sure it matches. Anyway, hope that helps!
Answer:
Step-by-step explanation:
(x - 2)/2 = 4
x - 2 = 8
x = 10
(y + 2)/2 = -3
y + 2 = -6
y = -8
(10, -8)
Answer:

Step-by-step explanation:

Note that
![x^{3/4 } = \sqrt[4]{x^3}](https://tex.z-dn.net/?f=x%5E%7B3%2F4%20%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%5E3%7D)
![y^{3/8 } = \sqrt[8]{y^3}](https://tex.z-dn.net/?f=y%5E%7B3%2F8%20%7D%20%3D%20%5Csqrt%5B8%5D%7By%5E3%7D)
So,
![\sqrt[4]{x^3} = \sqrt[8]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B8%5D%7By%5E3%7D)
![( \sqrt[4]{x^3} ) ^8= ( \sqrt[8]{y^3} )^8](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%20%5E8%3D%20%20%28%20%5Csqrt%5B8%5D%7By%5E3%7D%20%29%5E8)
![( \sqrt[4]{x^3} ) ^8= y^3](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%20%5E8%3D%20%20y%5E3)
Once
![( \sqrt[4]{x^3} )^8 = (( \sqrt[4]{x^3} )^4)^2= (x^3)^2 = x^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%5E8%20%3D%20%28%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%5E4%29%5E2%3D%20%28x%5E3%29%5E2%20%3D%20x%5E6)

![x = \sqrt[6]{y^3}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B6%5D%7By%5E3%7D)



Answer:
<u>18 and 19</u>
Step-by-step explanation:
Let the integers be x and x + 1.
=> 2(x + 1) = 3x - 16
=> 2x + 2 = 3x - 16
=> x = 18
=> x + 1 = 19
The integers are :-
<u>18 and 19</u>