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Jobisdone [24]
3 years ago
7

Jolly had some burgers. he ate two burgers and then he divided the remaining burger amongst his friends. he has five friends. ev

ery friend received two burgers. how many burgers did jolly start with
Mathematics
2 answers:
dexar [7]3 years ago
8 0
Jolly had 12 burgers from the start.

if his five friends ate 2, you'd multiply that and get 10, then you add how many Jolly ate, which is 12.
Zepler [3.9K]3 years ago
4 0

Answer:

12 burgers

Step-by-step explanation:

Let Jolly had x burgers. If he eats two burgers then remaining burgers = (x-2)

Now he divides these remaining burgers among his five friends. Then each friend gets 2 burgers.

So the equation will be

\frac{(x-2)}{5}=2

We further simplify this equation to get the value of x.

(x-2) = 2 × 5

(x-2) = 10

x = 10 + 2

x = 12

Therefore, there were 12 burgers.

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\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72

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2 years ago
Find the minimum value of the region formed by the system of equations and functions below.
Naily [24]

Answer:

  A.  -12

Step-by-step explanation:

A graph shows the vertices of the feasible region to be (0, 6), (3, 0) and (0, -3). Of these, the one that minimizes f(x, y) is (0, -3). The minimum value is ...

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_____

<em>Comment on the graph</em>

Here, three regions overlap to form the region where solutions are feasible. By reversing the inequality in each of the constraints, <em>the feasible region shows up on the graph as a white space</em>, making it easier to identify. The corner of the feasible region that minimizes the objective function is the one at the bottom, at (0, -3).

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3 years ago
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Yes. Since neither are rounded, 46.2 would be greater.
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1 year ago
Read 2 more answers
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