Question

A minor league baseball team plays 72 games in a season. If the team won 15 more than twice as many games as they lost, how many wins and losses did the team have?

Answer 1

X = games won
y = games lost

x + y = 72
x = 2y + 15

2y + 15 + y = 72
3y + 15 = 72
3y = 72 - 15
3y = 57
y = 57/3
y = 19 <=== lost games

x = 2y + 15
x = 2(19) + 15
x = 53 <=== won games