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Law Incorporation [45]
3 years ago
12

A minor league baseball team plays 72 games in a season. If the team won 15 more than twice as many games as they lost, how many

wins and losses did the team have?
Mathematics
1 answer:
Alina [70]3 years ago
3 0
X = games won
y = games lost

x + y = 72
x = 2y + 15

2y + 15 + y = 72
3y + 15 = 72
3y = 72 - 15
3y = 57
y = 57/3
y = 19 <=== lost games

x = 2y + 15
x = 2(19) + 15
x = 53 <=== won games
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krok68 [10]
For A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15

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Therefore our final answer is A-\frac{3}{a}+\frac{1}{a^2}-8a+15

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