3+5=8
8^2 is 8×8 which equals 64.
The square of the sum of 3 and 5 equals 64.
Answer:
3 the rest of his classmate
9514 1404 393
Answer:
a, c, b
Step-by-step explanation:
Collect terms, subtract the constant, divide by the y-coefficient.
(a) 4y + (y - 1) = 29 ⇒ y = 6
(c) (2y + 3) - 4 = 9 ⇒ y = 5
(b) 4y - y + 1 = 13 ⇒ y = 4 . . . . . this equation is not what you have written
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<em>Additional comment</em>
The second equation suffers from a typo, so your answer may vary.
If 19 is half (50%) of something, find that number you would just have to multiply 19 by 2.
This means that 19 is 50% of 38.
Answer: (x-2)^2+(y+3)^2 = 9Side notes
1) This circle has a center of (2,-3)
2) The radius of this circle is 3
3) The graph is shown in the attached image
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Work Shown:
x^2-4x+y^2+6y+4=0
x^2-4x+y^2+6y+4-4=0-4
x^2-4x+y^2+6y = -4
x^2-4x+4+y^2+6y = -4+4 ... see note 1 below
(x^2-4x+4)+y^2+6y = 0
(x-2)^2+y^2+6y = 0
(x-2)^2+y^2+6y+9 = 0+9 ... see note 2 below
(x-2)^2+(y^2+6y+9) = 9
(x-2)^2+(y+3)^2 = 9note 1: I'm adding 4 to both sides to complete the square for the x terms. You do this by first taking half of the x (not x^2) coefficient which in this case is -4. So take half of -4 to get -2. Then square this result to get 4
note 2: Like with note 1, I'm completing the square. What's different this time is that this is for the y terms now. The y coefficient is 6. Half of this is 3. Square 3 to get 9. So this is why we add 9 to both sides.
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So
the equation in standard form is (x-2)^2+(y+3)^2 = 9Note how
(x-2)^2+(y+3)^2 = 9
is equivalent to
(x-2)^2+(y-(-3))^2 = 3^2
So that second equation listed above is in the form (x-h)^2+(y-k)^2 = r^2
where
h = 2
k = -3
r = 3
making the center to be (h,k) = (2,-3) and the radius to be r = 3
The graph is attached.