1st box: 2a (subtract 2a from both sides)
2nd box: 3 (add 3 to both sides)
3rd box: 10 (add 7+3)
4th and 5th box: 2 (divide both by 2)
6th box: 5 (10/2=5)
Answer:
The first term, 5x^3, can be eliminated.
The exponent on the first term, 5x^3, can be changed to a 2 and then combined with the second term, 2x^2
Step-by-step explanation:
The highest degree allowed in a quadratic function is 2, so the third degree term (the first term) needs to be eliminated or changed. The change shown above is one of many possibilities.
Answer:
x=-2, y=-6
Step-by-step explanation:
Simple substitution.
Since y is isolated in one of the equations already, you can plug it into the second equation.
x - 2(3x) = 10
x - 6x = 10
-5x = 10
x = -2
Sub. x = -2 into 3x = y:
3(-2) = y
y = -6
The range for the data given is 11
