Answer:
8sin(x)cos³(x)
Step-by-step explanation:
sin(4x) +2 sin(2x) = 2sin(2x)*cos(2x) + 2sin(2x) = 2sin(2x)(cos2x + 1)=
= 2sin(2x)(cos²x - sin²x + cos²x + sin²x)=²2sin(2x)*(2cos²x)=
= 4*2sin(x)*cos(x)*cos²(x)= 8sin(x)cos³(x)
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
((4^7)/(5^2))^3 I'm pretty sure this is how you would right the problem to begin with
Answer:
C
Step-by-step explanation:
Here we have the question,
7x+4 = -19 + 5x
Now we add 19 to both sides,
7x + 4 + 19 = -19 + 19 + 5x
7x + 23 = 5x
Now we subtract 7x from both sides,
23 = -2x
We divide -2 from both sides,
x = -23/2
Now we plug this in into 2x - 14,
2(-23/2) - 14 = -23-14 = -37
Our answer is C
That is false. The parabola opens to the right.
