We need to identify what "the nearest cent" is.
So!
AB.CD
That is a representation of a number using variables, but we'll just say it's for place values.
A is in the Tens Place
B is in the Ones Place
C is in the Tenths Place (1/10)
D is in the Hundredths Place (1/100
Since we are talking about money let's put it in relation to a dollar.
A is in the Ten Dollar Place
B is in the One Dollar Place
C is in the Tenth of a Dollar Place (1/10 of a dollar)
D is in the Hundredth of a Dollar Place (1/100 of a dollar)
So, what is 1/10 of a dollar?
What amount of money times 10, would get you 1 dollar. Or you can think of it as if you had 10 of one value of money and you got a dollar what is that? A dime.
Now, what is 1/100 of a dollar?
What amount of money times 100, would get you 1 dollar. 1 cent (Or it is sometimes called a penny).
So that means any number beyond the 1/100 of a dollar point (D) will be rounded. If it's the first number after the 1/100 of a dollar is greater than (or equal to) 5 then we round the cent value up. If it is less than 5 we round down.
$29.4983
So, 9 is our cent place. 8 is greater than 5, so we round 9 up. (Add 1. Since it is 9 it will carry over into the 1/10 of a dollar place)
Our answer is:
$29.50
Under 45 mins is roughly 16%. This is because 68% of the curve exists within 1 SD of the mean. So 16% must be outside and smaller and 16% outside and larger (on average).
It is impossible to determine how likely you are to find someone with exactly the second amount. However, if you are looking for that or less, you would get 84%
Answer:
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Step-by-step explanation:
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2)BBC
3)odds
4)Goss
Recall the sum identity for cosine:
cos(a + b) = cos(a) cos(b) - sin(a) sin(b)
so that
cos(a + b) = 12/13 cos(a) - 8/17 sin(b)
Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,
cos²(a) + sin²(a) = 1 ⇒ cos(a) = √(1 - sin²(a)) = 15/17
cos²(b) + sin²(b) = 1 ⇒ sin(b) = √(1 - cos²(b)) = 5/13
Then
cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221