Mean = 62 in
SD = 2 in
At 16% = 0.16 and using Z tables,
Z≈ -0.99
x =(-0.99*2) + 62 ≈ 60 in
This represents jockeys who are shorter than 60 in.
(x-9) (x+2)=x²+2x-9x-18=x²-7x-18
The tangent line DC is perpendicular to the radius of the park
The length of AC is 245 feet
<h3>How to determine the distance AC?</h3>
To calculate the distance AC, we start by calculating the length of AB using:
DC^2 = (BC + AB) * BC
So, we have:
105^2 = (45 + AB) * 45
Evaluate the exponent
11025 = (45 + AB) * 45
Divide both sides by 45
245 = 45 + AB
Rewrite as:
AB + 45 = 245
From the figure, we have:
AC = AB + 45
Substitute AB + 45 = 245
AC = 245
Hence, the length of AC is 245 feet
Read more about line of tangents at:
brainly.com/question/6617153
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
