Suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 i
n.
Which group describes 16% of the population of horse jockeys?
Select each correct answer.
jockeys who are shorter than 58 in.
jockeys who are taller than 64 in.
jockeys who are shorter than 60 in.
jockeys who are between 60 in. and 64 in.
1 answer:
Mean = 62 in
SD = 2 in
At 16% = 0.16 and using Z tables,
Z≈ -0.99
x =(-0.99*2) + 62 ≈ 60 in
This represents jockeys who are shorter than 60 in.
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Step-by-step explanation:
3.65 is the correct answer to 0.146 divided by 0.04
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