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suter [353]
2 years ago
5

Simplify the expression –8(12). A. 96 B. 20 C. 2 D. –96

Mathematics
1 answer:
Tanzania [10]2 years ago
7 0
-96 is ur answer!!!!
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15a. Cindy can make $100 in four days babysitting. At that rate, how many day will it take
Sophie [7]

Answer:

4.2

Step-by-step explanation:

6 0
3 years ago
What is -5/8 + -8/9=
mariarad [96]

Answer:

-1.513888889 = -1.51

Step-by-step explanation:

-5/8 = -0.625

-8/9 = -0.8888888888

-0.625 + -0.8888888888 = -1.513888889

If you round this to the nearest tenth you get

<u>-1.51</u>

6 0
4 years ago
The equation x2 − xy + y2 = 3 represents a "rotated ellipse," that is, an ellipse whose axes are not parallel to the coordinate
Setler [38]

Answer:

the points where the ellipse crosses the x- axis are (1.73, 0) and (-1.73, 0)

Step-by-step explanation:

To find the points at which a graphic crosses the x-axis we need to find the values for x where y = 0.

Therefore, in the equation x²- xy + y² = 3 we are going to make y = 0 and solve for x

x² - xy + y² = 3

x²- x(0) + (0)² = 3

x² = 3

x = ±√3

x₁ = 1.73 and x₂ = -1.73

Therefore, the points where the ellipse crosses the x- axis are (1.73, 0) and (-1.73, 0)

3 0
4 years ago
Help me please !!!!!!!
sleet_krkn [62]
I think it's the third one too
4 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
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