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3 years ago

A truck needs 7 gallons of fuel to travel 56 miles. Can the truck travel 48 miles with 6 gallons of fuel? Explain.

2 answers:

ozzi3 years ago

6 0

The truck can travel 48 miles with 6 gallons.
Because if you divide 56(miles) by 7(gallons), you will get 8. 8 is the miles per gallon. so if you multiply 8(miles per gallon) by 6(gallons) you will get 48 which is how far the truck can travel on 8 gallons of fuel.

Hope this helps

nataly862011 [7]3 years ago

5 0

Answer:No; $\frac{7}{56}$ and $\frac{48}{6}$ are not proportional because 7x6 isn't equal to 48x6

Step-by-step explanation:

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A scale has a percent error of 7%. The scale reads the mass of a book as 450g. Which statement describes what the actual mass of

ozzi

Answer:

The actual mass of the book is between 481 . 5 g and 418 . 5 g.

Step-by-step explanation:

The mass of the book on the scale = 450 g

The percentage error in the scale = 7%

So, the actual mass of the book is 450 g ± 7%

Now, 7 % of the mass 450 g = $\frac{7}{100} \times 450 = 31.5$

⇒ 7% of 450 g = 31.5 g

Now, the Actual mass of the book = 450 g ± 31.5 g

450 g + 31.5 g = 481 . 5 g

450 g - 31.5 g = 418 . 5 g

Hence the actual mass of the book is between 481 . 5 g and 418 . 5 g.

5 0

3 years ago

Which is more 5 feet or 59 in

denis-greek [22]

5 feet is 12*5 which is 60
59 is less than 60
Do five feet is more

8 0

3 years ago

Read 2 more answers

the mean of the commute time to work for a resident of a certain city is 28.8 minutes. assume the standard deviation of the comm

hjlf

Answer:

The minimum percentage of the commuters in the city has a commute time within 2 standard deviations of the mean is 75%.

Step-by-step explanation:

We have no information about the shape of the distribution, so we use Chebyshev's Theorem to solve this question.

Chebyshev Theorem

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by $100(1 - \frac{1}{k^{2}})$ .

Applying the Theorem

The minimum percentage of the commuters in the city has a commute time within 2 standard deviations of the mean is 75%.

3 0

3 years ago

In a particular month, Ezhil spent one-fifth of her salary on shopping. Two-fifth of the remaining she gave to her sister. If sh

Oxana [17]

Answer:

$Salary = Rs23000$

Step-by-step explanation:

Given

$Shopping = \frac{1}{5}$

$Sister = \frac{2}{5}R$

$Left over = Rs11,040$

Required

Her salary in that month

Given that she spent $\frac{1}{5}$ of her salary on shopping, this implies that she has $\frac{4}{5}$ of her salary left

From what's left, she gave her sister $\frac{2}{5}$

This means she gave her sister $\frac{2}{5} * \frac{4}{5}$

Sister = $\frac{8}{25}$

Calculating a fraction of what's left

$Left over = 1 -Shopping - Sister$

$Left over = 1 - \frac{1}{5}- \frac{8}{25}$

$Left over = \frac{25 - 5 - 8}{25}$

$Left over = \frac{12}{25}$

Recall that she has Rs11,040

This means that

$\frac{12}{25} of Salary = Rs11,040$

Multiply both sides by $\frac{25}{12}$

$\frac{12}{25} * \frac{25}{12} * Salary = Rs11,040 * \frac{25}{12}$

$Salary = Rs11,040 * \frac{25}{12}$

$Salary = \frac{Rs276000}{12}$

$Salary = Rs23000$

Hence, her salary for that month was Rs23000

5 0

2 years ago

Read 2 more answers

A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line. He must recalibrate his machines

storchak [24]

Answer:

The null hypothesis is $H_o: \mu = 4$ .

The alternate hypothesis is $H_a: \mu \neq 4$

The pvalue of the test is 0.0182 < 0.05, which means that there is sufficient evidence to show that the manufacturer needs to recalibrate the machines.

Step-by-step explanation:

A manufacturer must test that his bolts are 4.00 cm long when they come off the assembly line.

This means that the null hypothesis is that they are 4.00 cm long, that is:

$H_o: \mu = 4$

At the alternate hypothesis we test if it is different. So

$H_a: \mu \neq 4$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

4 is tested at the null hypothesis:

This means that $\mu = 4$

After sampling 196 randomly selected bolts off the assembly line, he calculates the sample mean to be 4.14 cm.

This means that $n = 196, X = 4.14$

He knows that the population standard deviation is 0.83 cm.

This means that $\sigma = 0.83$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{4.14 - 4}{\frac{0.83}{\sqrt{196}}}$

$z = 2.36$

Pvalue of the test and decision:

The pvalue of the test is the probability that the sample mean is different by at least 4.14 - 4 = 0.14 from the target value, which is P(|z| > 2.36), which is 2 multiplied by the pvalue of z = -2.36.

Looking at the z-table, z = -2.36 has a pvalue of 0.0091

2*0.0091 = 0.0182

The pvalue of the test is 0.0182 < 0.05, which means that there is sufficient evidence to show that the manufacturer needs to recalibrate the machines.

5 0

2 years ago