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kow [346]
3 years ago
7

The mass of the cylinder is 50000 g find the density of the cylinder to the nearest tenth

Mathematics
1 answer:
vichka [17]3 years ago
6 0

Please consider the diagram of cylinder.

We have been given that the mass of the cylinder is 50000 g. We are asked to find the density of the cylinder.

\text{Density}=\frac{\text{Mass}}{\text{Volume}}

Let us find the volume of our given cylinder.

V=\pi r^2 h, where

r = Radius,

h = Height.

We know that radius is half the diameter, so radius of given cylinder would be \frac{28}{2}=14 mm.

V=\pi\cdot(14 \text{ mm})^2\cdot 30\text{ mm}

V=\pi\cdot 196\text{ mm}^2\cdot 30\text{ mm}

V=\pi\cdot 5880\text{ mm}^3

V=18472.5648031\text{ mm}^3

\text{Density}=\frac{50000\text{ g}}{18472.5648031\text{ mm}^3}

\text{Density}=2.7067167192510906\cdot \frac{\text{g}}{\text{ mm}^3}

\text{Density}\approx2.7\frac{\text{g}}{\text{ mm}^3}

Therefore, the density of the cylinder is approximately 2.7 gram per cubic mm.

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