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2 years ago

What is 8.786 rounded to nearest tenth

2 answers:

5 0

8.800 is the # rounded to the nearest tenth and it is that because 86 is above 50 so it is considered 8.800 OR 8.8. It is rounded up.

pentagon [3]2 years ago

4 0

8.8 because .78 rounded up is .8

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The quantity, Q, of a drug in the blood stream begins with 250 mg and decays to one-fifth its value over every 90 minute period.

Mazyrski [523]

Answer:

$a=250 \, mg\\\\b=5\\\\T= 90'$

Step-by-step explanation:

We have that $Q(t) = a\cdot b^{-\frac{t}{T}} \\$

Where t is the time (in minutes) and for the sake of dimensional consistency, let's assume that T is also in minutes, b is an adimensional number, and a is in mg. So we will have Q in mg as a consequence.

We now want to find out what values these constants might take. Let's see what happens when $t=0$ , that is, just as we start. At that point, we have that the amount of drug in the bloodstream must be equal to 250mg, thus:

$Q(0)= a\cdot b ^{-\frac{0}{T} }=250\,mg\\Q(0)= a=250\,mg$

We have found the constant $a$ ! It is the initial amount of drug! we have made use of the fact that any number raised to the 0th power is equal to one.

Now, we know that every 90 minutes, the amount of drug decreases to one fifth of its former value. How do we put this in mathematical form? Like so:

$Q(t+90')=Q(t)/5$

That is, 90 minutes after time t the amount of drug will be one fifth of the amount of drug at time t. Let's expand the last equation:

$Q(t+90')=Q(t)/5\\\\a\cdot b^{-\frac{t+90'}{T} }=a\cdot b^{-\frac{t}{T} }/5\\\\ b^{-\frac{t+90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{t}{T} }b^{-\frac{90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{90'}{T} }=\frac{1}{5}$

Now the last expression isn't enough to determine both T and b, but that also means that we have some freedom in how we choose them. What seems most simple is to pick $T=90'$ and thus we will get:

$b^{-1 }=\frac{1}{5}\\\\\frac{1}{b}= \frac{1}{5}\\\\b=5$

And that is our final result.

3 0

2 years ago

Help with math question

NNADVOKAT [17]

Well

You want to calculate the interest on $1000 at 3.5% interest per month after 3 year(s).

The formula we'll use for this is the simple interest formula, or:

Where: P is the principal amount, $1000.00.

r is the interest rate, 3.5% per month, or in decimal form, 3.5/100=0.035.

t is the time involved, 3....year(s) time periods.

Since your interest rate is "per month" and you gave your time interval in "year(s)" we need to convert your time interval into "month" as well.

Do this by multiplying your time, 3 year(s), by 12, since there's 12 months in 1 year.

So, t is 36....month time periods.

To find the simple interest, we multiply 1000 × 0.035 × 36 to get that:

The interest is: $1260.00

Hope i could help

6 0

2 years ago

If you roll a 6 sided die 4 times what is the probability of getting 3 2’s

sp2606 [1]

Answer:

1/6 x 1/6 x 1/6 = 1/36 x 1/6 = 1/216

You multiply the chances

Hope this helped

Step-by-step explanation:

5 0

2 years ago

BINOMIAL MULTIPLICATION 1. (2x + 1)(x + 3)

goldfiish [28.3K]

2x^2 + 7x + 3 ; you multiple each the terms in the first set or parentheses by the other

4 0

2 years ago

How do you do this? please help me

Anastaziya [24]

Answer:

f = 10, g = 4.8 cm

Step-by-step explanation:

Area of ABCE = 60 cm²

Area of ABCD = 48 cm²

So,

Area of ADE = 60-48

=> 12 cm²

Area of ADE = $\frac{1}{2} (Base)(Height)$

Where Area = 12 cm², Base = 4 cm

12 = $\frac{1}{2}(4)(Height)$

Height = 12-2

Height = 10 cm

Where Height is AD

So, AD = 10 cm

Also, AD is parallel and equal to BC $(f)$

So,

f = 10 cm

Now, Finding g

Area of ABCD = $Base * Height$

Where Area = 48 cm², Base = 10 cm

48 = 10 * Height

Height = 48/10

Height = 4.8 cm

Whereas, Height is g

So, g = 4.8 cm

8 0

2 years ago