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Luden [163]
3 years ago
11

HELP FOLLOW PEMDAS RULES 6 ÷ 2(1+2) = GOOD LUCK :)

Mathematics
2 answers:
inysia [295]3 years ago
8 0

Answer:

9

Step-by-step explanation:

PEMDAS IS

parentheses

Exponents

Multiply and divide

Addition and subtraction

First you start with the parentheses so

1 + 2 = 3

Now you have 6/2 x 3

Multiply and divide means you either divide or multiply what ever comes first going left to right

So

6/2 = 3

3 x 3 = 9

If it was reversed we’d have

2 x 3/6 which would be

6/6 = 1

Lina20 [59]3 years ago
7 0

Answer:

its 9

Step-by-step explanation:

6÷2(1+2)

6÷2×3

3×3

9

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answer to #10 and #13. can’t figure out how to use interval notation to write domain and range for graphs.
Lyrx [107]
Interval notation is used to write a set of real numbers from one value to another value.
On the left, you start with left parenthesis or left bracket.
Then you follow by two numbers separated by a comma.
You then finish with a right parenthesis or right bracket.
To include a number, use a square bracket.
To exclude a number use parenthesis.
To write the set of numbers, you need to list the smallest number in the set followed by the largest number in the set. An interval is always stated with two numbers, from the smallest in the set to the largest in the set. The numbers are always separated by a comma.

Examples:

1) All numbers from 6 to 10, including 6 and 10.
Algebra: 6 <= x <= 10
Interval: [6, 10]
Notice brackets since both 6 and 10 are included in this interval.

2) All number from 5 to 20, including 5 but not including 20.
Algebra 5 <= x < 20
Interval: [5, 20)
Bracket with 5 means include 5. Parenthesis with 20 means 20 is not included.

3) All numbers greater than or equal to 7.
Algebra: x >= 7
Interval: [7, ∞)
The 7 has a bracket because it is included. Infinity always has parenthesis.
With the infinity symbol, always use parenthesis, not square bracket.

4) All numbers less than -5.
Algebra: x < - 5
Interval: (-∞, 5)

Now for your problems.

10.
This is a line. Both the domain and range all all real numbers.
That means the interval is from negative infinity to positive infinity.
(-∞, ∞)
Both the domain and range are that same interval, all real numbers, from negative infinity to positive infinity.

13.
The domain is all real numbers as you can see the x-coordinates extend left forever and right forever. The domain is the same interval as the domain and range of problem 10.

The range is zero and all positive numbers.
You can think of it a all values of y such that y is greater than or equal to zero. Notice that zero is included in the interval.

[0, ∞)

Since zero is included, we use a left bracket, not left parenthesis.
With infinity, we alyways use parentheses, not brackets.
8 0
3 years ago
Solve for b:<br>10abc - 2d = 3d​
gulaghasi [49]

Answer:

b = d/(2ac)

Step-by-step explanation:

10abc - 2d = 3d

Add 2d to each side

10abc - 2d+2d = 3d+2d

10 abc = 5d

Divide each side by 10ac

10 abc/ (10ac) = 5d/10ac

b = d/(2ac)

3 0
3 years ago
Paul opened a bakery. The net value of the bakery (in
Umnica [9.8K]

Answer:

1) 2(t - 7)(t + 1)

2) $32,000

Step-by-step explanation:

v(t) = 2t² - 12t - 14

v(t) = 2(t² - 6t - 7) = 2(t - 7)(t + 1)

x = -b/2a = 6/2 = 3

y = 2(3)² - 12(3) - 14 = -32

(3, -32) means at 3 months, -32 thousand dollars

7 0
3 years ago
Read 2 more answers
Consider to circular swimming pools.Pool A has a radius of 12 feet and Pool B has a diameter of 7.5 meters which pool has a grea
mamaluj [8]

C = Pi * d  where C = circumference, d = diameter, r = radius

C = 2*pi *r

we need to watch the units since they are different

Pool A

C = 2 * pi * r

C = 2 * pi * 12  = 24 * pi  in feet


Pool B

C = pi * d

change meters to feet

7.5 m * 3.28 ft/ 1 m  = 24.6 ft

C = pi * 24.6  = 24.6* pi  in ft


Pool B had a greater circumference

24.6 * pi > 24 pi


6 0
3 years ago
Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet
Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\

Take the second derivative of the function, to check if it will given a minimum perimeter

\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)

Determine the critical points of the first derivative;

df/dw = 0

\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0
3 years ago
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