First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate. Then, you substitute all the values that you provided for the angles. 15x+15=x+15+140. You then solve for x.

15x+15=x+155

14x=140

x=10

You then plug back in 10 for X in the value of m<UTS. 15(10)+15=165

3 0

3 years ago

7p + 3(-6p + 2) > 7p+9+1<br> Someone help me

olga_2 [115]

Answer:

p > -0.2222

Step-by-step explanation:

7p + 3(-6p + 2) > 7p + 9 +1

7p + (3*-6p + 3*2) > 7p + 10

7p - 18p + 6 > 7p + 10

-11p - 7p > 10 - 6

-18p > 4

p > 4/-18

p > -0.2222

3 0

3 years ago

Solve <br> 28 - K _> 7(K - 4)

Evgen [1.6K]

Answer:

Solving the inequality $28-K\geq 7(K-4)$ , we get $\mathbf{K\leq 7}$

Step-by-step explanation:

We need to solve the inequality $28-K\geq 7(K-4)$

Using the BODMAS rule, first we will solve the bracket:

$28-K\geq 7(K-4)\\28-K\geq 7K-28$

Now, we will subtract 28 from both sides

$28-K-28\geq 7K-28-28\\-K\geq 7K-56$

Subtracting -7k on both sides

$-K-7K\geq 7K-56-7K\\-8k\geq -56$

Finally, divide both sides by -8 and inverse the inequality, as we are dividing with a minus digit.

$\frac{-8K}{-8}\leq \frac{-56}{-8}\\K\leq 7$

So, solving the inequality $28-K\geq 7(K-4)$ we get $\mathbf{K\leq 7}$

7 0

3 years ago