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IgorLugansk [536]
3 years ago
6

What is the length of BC ? Round to the nearest tenth. 16 cm

Mathematics
1 answer:
serg [7]3 years ago
4 0

Since Sin is equal to opposite over hypotenuse

so that's mean Sin(60°) = \frac{x}{16}

#I just rounddown from angle 65° to 60° as the number is not that much different.

and Sin(60°) is equal to \frac{\sqrt{3} }{2}

so we got Sin(60°) = \frac{\sqrt{3} }{2} = \frac{x}{16}

x = \frac{16\sqrt{3} }{2}

x ≈ 14

then we can answer C)14.5

the answer D) is not correct for sure because the opposite cannot be longer than hypotenuse in the Right Triangle form.

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9514 1404 393

Answer:

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Step-by-step explanation:

The angle bisector divides the triangle sides proportionally.

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  x = 30(24/32)

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5 0
2 years ago
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3 years ago
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kupik [55]
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4 0
3 years ago
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allochka39001 [22]

Answer:

\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}

Step-by-step explanation:

\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o

4 0
3 years ago
A negative divided by a negative is always positive.<br><br> Is positive or negative
masha68 [24]

Answer:

it will negative........

I have read this many times and I'm sure that I'm correct

6 0
3 years ago
Read 2 more answers
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