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alina1380 [7]
3 years ago
10

I don’t know what to do

Mathematics
1 answer:
alex41 [277]3 years ago
3 0

Answer:

I think that it is non tangent

Step-by-step explanation:

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Step-by-step explanation:

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If the substitution u=x/2 is made, the intergal from 2 to 4 1-(x/2)^2/x dx =
stich3 [128]
\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx

Setting u=\dfrac x2 gives \mathrm du=\dfrac{\mathrm dx}2, or 2\,\mathrm du=\mathrm dx. This also makes 2u=x.

When x\to2^+, you have u\to\dfrac22=1, while when x\to4^-, you have u\to\dfrac42=2.

Putting everything together, you find that

\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx=\int_1^2\frac{1-u^2}{2u}(2\,\mathrm du)=\int_1^2\frac{1-u^2}u\,\mathrm du

which means (B) is the correct answer.
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